先有的图片,然后才有的以下程序,不知道之前有没有人做过,大家学习一下啊。。public class Math {
private static int pre=1;
public static int getResult(int pre2,int suf){
return pre2*8+suf;
}
public static void main(String[] args) {
for(int i = 1;i <= 9;i++){
for(int j = 9-i; j >= 1;j--){
System.out.print(" ");
}
System.out.println(pre+"*8+"+i+"="+getResult(pre, i));
pre = pre*10+(i+1);
}
}
}
for (int i = 1; i < 10; i++) {
pre += i;
System.out.println(Integer.parseInt(pre));
}到底是每次乘10加上个位好点,还是每次进行字符串的连接好点,等待牛人分析了
String pre2 = new String();
for (int i = 1; i < 10; i++) {
for (int j = 0; j < 9 - i; j++) {
System.out.print(" ");
}
pre += i;
pre2 += 10 - i;
System.out.println(pre + " X 8 + " + i + " = " + pre2);
}
int result = j * 8 + i;
System.out.printf("%9d * 8 + %d = %d\n", j , i ,result);
}
public static void main(String[] args) {
int n = 8;
int sum = 0;
String str = "";
for (int i = 1; i < 10; i++) {
for (int j = i; j < 9; j++) {
System.out.print(" ");
}
str += i;
sum = Integer.parseInt(str)*8+i ;
System.out.println(""+str+"*"+n+"="+sum+"");
}
}
}
public static void main(String[] args)
{
int i;
int j=1;
int y;
for(i=1;i<10;i++)
{
for(y=9;y-i>0;y--)
{
System.out.print(" ");
}
System.out.println(j+"*8+"+i+"="+(j*8+i));
j=j*10+i+1;
}
}
}
{
public static void main(String[] args)
{
TestPrint.print(9);
}
public static void print(int layer)
{
for (int i = 1; i <= layer; i++)
{
//打印空格
for (int j = 1; j <= layer-i; j++)
{
System.out.print(" ");
}
//打印被乘数
for (int j = 1; j <= i; j++)
{
System.out.print(j);
}
System.out.print(" X 8 + ");
System.out.print(i);
System.out.print(" = ");
//打印结果
for (int k = 9; k > 9-i; k--)
{
System.out.print(k);
}
System.out.println();
}
}
}