菜鸟问题:当方法执行完毕后,该怎么让程序继续下去或者重复?

Question

public void startOrder(LinkedHashMap<String,Food> passinFood){                int custID=0;
                System.out.println("Welcome");
System.out.println("press 1 to buy");

Scanner keyboard = new Scanner(System.in);

custID = keyboard.nextInt();
if(custID==1){
displayOrderMenu(passinFood);
}
        }
public void displayOrderMenu(LinkedHashMap<String,Food> passinFood)
{
.....
}displayOrderMenu执行结束后,怎样去重新开始startOrder? 
用这个?this.startOrder(passinFood)

Answer 1

方法很多最菜鸟的是这样。
public static void main(String[] args){
    类名 instance = new 类名();
    int count = 100;//任何你想的数字
    while(count>0){
     instance.startOrder(passinFood);
     count--;
   }
}

Answer 2

public void displayOrderMenu(LinkedHashMap<String,Food> passinFood)
{
.....
this.startOrder(passinFood);
}
是这个意思？

Answer 3

如果这样的话,那displayOrderMeny() 需要带两个参数了, 因为startOrder()是两个参数.估计初学者开始都会遇到这个破问题,但是经常表述不清楚 - - 

Answer 4

public void startOrder(LinkedHashMap<String,Food> passinFood){                int custID=0;
                System.out.println("Welcome");
        System.out.println("press 1 to buy");
        
        Scanner keyboard = new Scanner(System.in);
        
        custID = keyboard.nextInt();
        if(custID==1){        
        displayOrderMenu(passinFood);
          //这意思？
           startOrder(passinFood);//自己掉自己 直到不满足条件
        }
         
              
        }
可能是没看明白你的意思

Answer 5

楼主的意思是不是这样的：
 public void startOrder(LinkedHashMap<String,Food> passinFood){
 ........
 displayOrderMenu(passinFood);
}
public void displayOrderMenu(LinkedHashMap<String,Food> passinFood)
{
.....
}执行完displayOrderMenu(passinFood)后，程序又重新开始执行startOrder....
public static void main(String[] args){
    类名 instance = new 类名();
    boolean flag = true ;
   while(flag){
    instance.startOrder
}