我在文件中加入了如下代码<script type="text/javascript">
var _gaq = _gaq || [];
_gaq.push(['_setAccount', 'UA-xxxxxxx-x']);
_gaq.push(['_trackPageview']);
(function() {
var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true;
ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js';
var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s);
})();
</script>
链接修改成如下
<a href="../download/wenjian/gnqy.zip" onClick="javascript: pageTracker._trackPageview('/download/wenjian/gnqy.zip'); ">为什么不能统计出结果,哪里出错了?
var _gaq = _gaq || [];
_gaq.push(['_setAccount', 'UA-xxxxxxx-x']);
_gaq.push(['_trackPageview']);
(function() {
var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true;
ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js';
var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s);
})();
</script>
链接修改成如下
<a href="../download/wenjian/gnqy.zip" onClick="javascript: pageTracker._trackPageview('/download/wenjian/gnqy.zip'); ">为什么不能统计出结果,哪里出错了?
Try:
<script type="text/javascript">
var gaJsHost = (("https:" == document.location.protocol) ? "https://ssl." : "http://www."); document.write(unescape("%3Cscript src='" + gaJsHost + "google-analytics.com/ga.js' type='text/javascript'%3E%3C/script%3E"));
</script>
<script type="text/javascript">
try {
var pageTracker = _gat._getTracker("UA-12547002-1");
pageTracker._trackPageview(); } catch(err) {}
</script>还有检视下路径是否正确
<a href="../download/wenjian/gnqy.zip" onClick="javascript: pageTracker._trackPageview('/download/wenjian/gnqy.zip'); ">
var _gaq = _gaq || [];
_gaq.push(['_setAccount', 'UA-xxxxxxx-x']);
_gaq.push(['_trackPageview']);
(function() {
var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true;
ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js';
var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s);
})();
</script>这段代码是google提供的标准的,还要替换成上面的样子吗?google的服务是最差的,只知道售前,连个技术支持都没有,垃圾google。