监听List列表跳转问题，点列表1跳转到1个activity，点列表2跳到activity2

Question

本帖最后由 qq81819999 于 2013-04-17 15:11:38 编辑

Answer 1

根据positon来判断。position == 0跳转第一个  等于1跳转第二个

Answer 2

switch (position) {
                    case 1:
                        //跳转逻辑
                        break;
                    case 2:
                        //跳转逻辑
                        break;
                }以此类推

Answer 3

LS说的基本是对的   前提条件是你的ListView列表需是固定不变的~

Answer 4

可以参考下如下代码package com.tarena.android;import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.widget.AdapterView;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.AdapterView.OnItemClickListener;import com.tarena.android.entity.Student;public class ListViewTest extends Activity{
private ListView lv;
private List<Student> stus; @Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
stus=new ArrayList<Student>();
stus.add(new Student(1001,"zhangsan",20,85));
stus.add(new Student(1002,"lisi",21,87.5));
stus.add(new Student(1003,"wangwu",22,88));
stus.add(new Student(1004,"zhaoliu",20,75));
stus.add(new Student(1005,"qianqi",21,97.5));
stus.add(new Student(1006,"liuba",22,68));

setContentView(R.layout.list_view_test);

lv=(ListView)findViewById(R.id.list_view_01);

List<Map<String,Object>> data=new ArrayList<Map<String,Object>>();
for(int i=0;i<stus.size();i++){
Map<String,Object> map=new HashMap<String,Object>();
map.put("s_id", stus.get(i).getId());
map.put("s_name", stus.get(i).getName());
map.put("s_age", stus.get(i).getAge());
map.put("s_score", stus.get(i).getScore());
data.add(map);
}

SimpleAdapter adapter=new SimpleAdapter(this,data,R.layout.list_view_item_02,new String[]{"s_id","s_name","s_age","s_score"},new int[]{R.id.s_id_text_2,R.id.s_name_text_2,R.id.s_age_text_2,R.id.s_score_text_2});
lv.setAdapter(adapter);

lv.setOnItemClickListener(new OnItemClickListener(){ @Override
public void onItemClick(AdapterView<?> arg0, View arg1, int arg2,
long arg3) {
Intent it=new Intent(ListViewTest.this,StudentDescribeActivity.class);
it.putExtra("student", stus.get(arg2));
startActivity(it);

}

});

}
}

Answer 5

position == 0时处理跳转

Answer 6

不明白你所指的列表改变是什么意思，即使往下拉listview position 也是固定的吧？