在js里面如果取得table里面的checkbox集会

Question

在js里面如果取得table里面的checkbox集会,方便判断是否有选择项<table id="Office_Voting1_ItemCheckBoxList" border="0">
<tr>
<td><input id="Office_Voting1_ItemCheckBoxList_0" type="checkbox" name="Office_Voting1$ItemCheckBoxList$0" /><label for="Office_Voting1_ItemCheckBoxList_0">很好</label></td>
</tr><tr>
<td><input id="Office_Voting1_ItemCheckBoxList_1" type="checkbox" name="Office_Voting1$ItemCheckBoxList$1" /><label for="Office_Voting1_ItemCheckBoxList_1">好</label></td>
</tr><tr>
<td><input id="Office_Voting1_ItemCheckBoxList_2" type="checkbox" name="Office_Voting1$ItemCheckBoxList$2" /><label for="Office_Voting1_ItemCheckBoxList_2">一般</label></td>
</tr><tr>
<td><input id="Office_Voting1_ItemCheckBoxList_3" type="checkbox" name="Office_Voting1$ItemCheckBoxList$3" /><label for="Office_Voting1_ItemCheckBoxList_3">差</label></td>
</tr><tr>
<td><input id="Office_Voting1_ItemCheckBoxList_4" type="checkbox" name="Office_Voting1$ItemCheckBoxList$4" /><label for="Office_Voting1_ItemCheckBoxList_4">很差</label></td>
</tr>
</table>

Answer 1

var value=""; 
var c=document.getElementById("Office_Voting1_ItemCheckBoxList").document.getElementsByTagName("input");
    for(var i=0;i<c.length;i++){
     if(c[i].type=="checkbox"&&c[i].checked){
     value+=c[i].value+",";
     }
    }
alert(value)