【正则】连续相同的数字

Question

例如：
55.0000 替换成55 
55.0600 替换成55.06
55.0678 替换成55.0678 
55.0670 替换成55.0670
55.1000 替换成55.1
Regex.Replace(s, @"", "", RegexOptions.IgnoreCase);

Answer 1

Regex.Replace(s, @"(?<=\.\d*)(\d)(\1)+", "").TrimEnd('.');

Answer 2

  string tempStr = File.ReadAllText(@"C:\Documents and Settings\Administrator\桌面\Test.txt", Encoding.GetEncoding("GB2312"));
                string pattern = @"\d+(.\d+)?";
                List<float> temp_result = Regex.Matches(tempStr,pattern).Cast<Match>().Select(a=>float.Parse(a.Value)).ToList();
                /*
                   [0] 55.0 float
                [1] 55.06 float
                [2] 55.0678 float
                [3] 55.067 float
                [4] 55.1 float                 */

Answer 3

个人认为，你的问题，就是去除数字多余的0，这用数字好解决这个问题，用正则反而不好解决。[code=C#]var source = "55.3000";
var result = decimal.Parse(source).ToString("0.0");/code]

Answer 4

void Main()
{
var list=new List<string>{ 
"55.0000",
"55.0600",
"55.0678",
"55.0670",
"55.1000"
};
var reg=new Regex(@"(?<=\.\d*)(\d)(\1)+");
list.ForEach(l=>Console.WriteLine("{0}:\t{1}",l,reg.Replace(l,"").TrimEnd(new char[]{'.','0'})));
/*
55.0000: 55
55.0600: 55.06
55.0678: 55.0678
55.0670: 55.067
55.1000: 55.1
*/
}

Answer 5

其实这根本不需要正则，直接这样即可："55.1030".TrimEnd(new char[]{'.','0'})

Answer 6

忘记了，把格式串换成0.#即可
var source = "55.3000";
var result = decimal.Parse(source).ToString("0.#");

Answer 7

你思路对了 有个地方你疏忽了
我只替换掉0  所以我给你改了下(?<=\.\d*)([0])([0])+

Answer 8

哈哈哈 很好 我还以为这个TrimEnd 只会去掉最后一位呢