.net用AJAX怎样做到无刷新删除啊，

我点击删除后，只有刷新一下才能看到删除效果。
 
 //根据ID删除方法
       function doDel(id){
          if(confirm("您确定要删除吗?")){
              xhr.open("get","list.ashx?do=d&id="+id+"",true);
              xhr.setRequestHeader("If-Modified-Since","0");  //不使用缓存
              xhr.onreadystatechange=function(){
              if(xhr.readyState==4){
                   if(xhr.status==200){
                      var res=xhr.responseText;
                      //若果是这样alert(res)说出的话，得到的还是一个字符串{status:1},所以
                      //我们还要用eval方法转一下,成json对象
                      //alert(res);
                      
                     var json=eval("("+res+")");
                     //遍历,判断返回的是什么值 1还是-1
                     switch(res.status){
                          case -1:
                            alert("参数错误");
                             window.location="list.htm";   //跳转到当前页面，即刷新一下
                          break;
                          case 0:
                             alert("删除失败，请稍后再试");
                          break;
                          case 1:
                             removeRowById(id);                          
                          break;
                     }
                       
                   }
              }
            }
             xhr.send(null);
          }
       }
  //删除后删除行
       function removeRowById(id){
           var tbL=document.getElementById("tbList");  //获得表格对象
           for(i=0;i<tbL.rows.length;i++)
           {
               if(tbL.rows[i].childNodes[1].innerHTML==id){
                  //tbL.deleteRow(i);   //删除 对应下标 的行对象
                  document.getElementById(" tbL.deleteRow(i)").hidden=true;
                  break;
               }
           }
       }
//
cs
  //删除业务事件
        void SoftDell(HttpContext context)
        {
            //获取页码
            string strId = context.Request.QueryString["id"];       //id是传递的参数名，要与前面一致
            int intid = 0;
            //将字符串id 转成 整形id
            if (!int.TryParse(strId, out intid))
            {
                //若果参数错了
                context.Response.Write("{status:-1}");             
            }
            else 
            {
                string sqlstr = "delete from board where BoardId=" + strId + "";
                Common common = new Common();
                //return common.ExecuteNonQuery(sqlstr);                //因为调用删除的方法成功则是返回非-1的任何数，反之，返回-1则失败              
                if ((common.ExecuteNonQuery(sqlstr)) != -1)   //执行数据库删除
                {
                    //删除成功
                    context.Response.Write("{status:1}");
                }
                else
                {
                    //删除失败
                    context.Response.Write("{status:0}");
                }
            }               }