c#上传下载

Question

private void Form1_Load(object sender, EventArgs e)
        {
            SqlConnection con = new SqlConnection("server=.;uid=sa;pwd=;database=jinjiedb");
            con.Open();
            SqlCommand cmd = new SqlCommand("select username from users", con);
            DataTable dt = new DataTable();
            SqlDataAdapter sda = new SqlDataAdapter(cmd);
            sda.Fill(dt);
            dataGridView1.DataSource = dt;
        }
        public static bool UploadFile(string localFilePath, string serverFolder,bool reName)
        {
            string fileNameExt, newFileName, uriString;
            if (reName)
            {
                fileNameExt = localFilePath.Substring(localFilePath.LastIndexOf(".") + 1);
                newFileName = DateTime.Now.ToString("yyMMddhhmmss") + fileNameExt;
            }
            else
            {
                newFileName = localFilePath.Substring(localFilePath.LastIndexOf("\\")+1);
            } 
            if (!serverFolder.EndsWith("/") && !serverFolder.EndsWith("\\"))
            {
                serverFolder = serverFolder + "/";
            }            uriString = serverFolder + newFileName;   //服务器保存路径
            /**//// 创建WebClient实例
            WebClient myWebClient = new WebClient();
            myWebClient.Credentials = CredentialCache.DefaultCredentials;            // 要上传的文件
            FileStream fs = new FileStream(newFileName, FileMode.Open, FileAccess.Read);
            BinaryReader r = new BinaryReader(fs);
            try
            {
                //使用UploadFile方法可以用下面的格式
                //myWebClient.UploadFile(uriString,"PUT",localFilePath);
                byte[] postArray = r.ReadBytes((int)fs.Length);
                Stream postStream = myWebClient.OpenWrite(uriString, "PUT");
                if (postStream.CanWrite)
                {
                    postStream.Write(postArray, 0, postArray.Length);
                }
                else
                {
                    MessageBox.Show("文件目前不可写！");
                }
                postStream.Close();
            }
            catch
            {
                //MessageBox.Show("文件上传失败，请稍候重试~");
                return false;
            }            return true;
        }这个是我从网上找的，具体怎么用 不清楚
望大侠指点一下

Answer 1

我QQ506795
MSN [email protected]
谢谢大侠们

Answer 2

复制错了 把上面的Form1_Load也复制进去了。

Answer 3

        private void button1_Click(object sender, EventArgs e)
        {
            openFileDialog1.ShowDialog();
            UploadFile(openFileDialog1.FileName, "d:\\1", false);
        }
        public static bool UploadFile(string localFilePath, string serverFolder, bool reName)
        {
            string fileNameExt, newFileName, uriString;
            if (reName)
            {
                fileNameExt = localFilePath.Substring(localFilePath.LastIndexOf(".") + 1);
                newFileName = DateTime.Now.ToString("yyMMddhhmmss") + fileNameExt;
            }
            else
            {
                newFileName = localFilePath.Substring(localFilePath.LastIndexOf("\\") + 1);
            }
            if (!serverFolder.EndsWith("/") && !serverFolder.EndsWith("\\"))
            {
                serverFolder = serverFolder + "/";
            }            uriString = serverFolder + newFileName;   //服务器保存路径
            /**/
            /// 创建WebClient实例
            WebClient myWebClient = new WebClient();
            myWebClient.Credentials = CredentialCache.DefaultCredentials;            // 要上传的文件
            FileStream fs = new FileStream(localFilePath, FileMode.Open, FileAccess.Read);
            // FileStream fs = new FileStream(newFileName, FileMode.Open, FileAccess.Read);
            BinaryReader r = new BinaryReader(fs);
            try
            {
                //使用UploadFile方法可以用下面的格式
                //myWebClient.UploadFile(uriString,"PUT",localFilePath);
                byte[] postArray = r.ReadBytes((int)fs.Length);
                //    Stream postStream = myWebClient.OpenWrite(uriString, "PUT");
                Stream postStream = myWebClient.OpenWrite(uriString, "PUT");
                if (postStream.CanWrite)
                {
                    postStream.Write(postArray, 0, postArray.Length);
                }
                else
                {
                    return false;
                }
                postStream.Close();
            }
            catch
            {
                //    //MessageBox.Show("文件上传失败，请稍候重试~");
                return false;
            }            return true;
        }这样能传到本地d盘文件夹1下面
如何上传到远程服务器上呢
把"d:\\1"换成ftp://123.456.789.20/wtt为什么就不行呢？
当然这个ftp是个假的  

Answer 4

myWebClient.Credentials = CredentialCache.DefaultCredentials; 
一般FTP服务器都需要密码的，这样做不行。
myWebClient.Credentials =new NetworkCredential(username,password);//对应ftp服务器上的用户名和密码

Answer 5

下面的代码示例使用 UploadFile 将指定的文件上载到指定的 URI。由服务器返回的任何响应都显示到控制台。Console.Write("\nPlease enter the URI to post data to : ");
String uriString = Console.ReadLine();// Create a new WebClient instance.
WebClient myWebClient = new WebClient();
myWebClient.Credentials =new NetworkCredential(username,password);//对应ftp服务器上的用户名和密码Console.WriteLine("\nPlease enter the fully qualified path of the file to be uploaded to the URI");
string fileName = Console.ReadLine();
Console.WriteLine("Uploading {0} to {1} ...",fileName,uriString);// Upload the file to the URI.
// The 'UploadFile(uriString,fileName)' method implicitly uses HTTP POST method.
byte[] responseArray = myWebClient.UploadFile(uriString,fileName);// Decode and display the response.
Console.WriteLine("\nResponse Received.The contents of the file uploaded are:\n{0}", 
    System.Text.Encoding.ASCII.GetString(responseArray));

Answer 6

按道理说上传和下载应该是两个不同的方法 public static bool UploadFile(string localFilePath, string serverFolder,bool reName)
只是从本地用流读入文件上传到服务器

Answer 7

string username="*****";
            string password="********T";
            string uri = "ftp://******/wtt/UnicodeDemo.cs";
            string fileName = "C:\\UnicodeDemo.cs";
            WebClient client = new WebClient();
            client.Credentials = new NetworkCredential(username, password);
            byte[] result=null;
            try
            {
                result = client.UploadFile(uri, fileName);
            }
            catch (WebException exc)
            {
                MessageBox.Show(exc.Status.ToString());
            }
            string resultString = System.Text.Encoding.ASCII.GetString(result);
            MessageBox.Show(resultString);是可以的。