怎么用TEXTBOX显示OPENFILEDIALOG所选择文件的路径

Question

RT:最好给代码语句

Answer 1

TextBox1.Text=OPENFILEDIALOG1.FileName

Answer 2

        private void btnExcelPathImport_Click(object sender, EventArgs e)
        {
            ofdExcelImport = new OpenFileDialog();
            ofdExcelImport.Filter = "Excel文件(*.xls)|*.xls";
            if (ofdExcelImport.ShowDialog() == DialogResult.OK)
            {
                txtExcelPath.Text = ofdExcelImport.FileName;
            }
        }

Answer 3

我在做打开文件夹对话框的用的语句中OPENFILEDIALONG.FILENAME怎么处理才能显示路径

Answer 4

            string[] urlA;
            if (openFileDialog1.ShowDialog() == DialogResult.OK)
            {
                urlA = openFileDialog1.FileNames;
                string m_路径 = urlA[0];
                txt路径.Text = m_路径;
            }