调用"Open With"窗口 ！(加急)

Question

OpenFileDialog openFileDialog1 = new OpenFileDialog();openFileDialog1.Filter = "txt files (*.txt)|*.txt" ;

if(openFileDialog1.ShowDialog() == DialogResult.OK)
{}
接分

Answer 1

if(this.openFileDialog1.ShowDialog()==DialogResult.OK)
{
mc=new MdiChild();
mc.MdiParent=this;
(this.openFileDialog1.FileName);
mc.richTextBox1.LoadFile(this.openFileDialog1.FileName,RichTextBoxStreamType.PlainText);
mc.Show();
mc.Text=this.openFileDialog1.FileName;
}

Answer 2

不是这个！是弹出的关联程序窗口！比如a.bmp  可以用autosee  和 画图板 等打开
怎样调用这个选择框！