实现计算器,实现加减乘除.

Question

我想问可以用static函数做吗?

Answer 1

using System;
using System.Collections.Generic;
using System.Text;namespace test
{
    class Program
    {
        static void Main(string[] args)
        {
        label:
            Console.WriteLine("请逐一的输入你要计算的数字与运算符:");
            int a=Convert.ToInt32( Console.ReadLine());
         char sign = Convert.ToChar(Console.ReadLine());
         int b= Convert.ToInt32(Console.ReadLine());
         Console.Clear();
         Console.WriteLine("输出的结果为:");
         switch (sign)
         { 
             case '+':
                 int c = Compute1(a, b);
                 Console.WriteLine("{0}+{1}={2}",a,b,c);
                 break;
             case '-':
                  c = Compute2(a, b);
                  Console.WriteLine("{0}-{1}={2}", a, b, c);
                 break;
             case '*':
                 c = Compute3(a, b);
                 Console.WriteLine("{0}*{1}={2}", a, b, c);
                 break;
             case '/':
                c = Compute4(a, b);
                Console.WriteLine("{0}/{1}={2}", a, b, c);
                 break;
             default:
                     Console.Clear();
                     Console.WriteLine("您输入的数据不正确,请重新输入一次.....");
                     break;
                 
         }
         goto label;
                //Console.ReadKey();
        }        static int Compute1(int i, int j)
        {
            return i + j;
        }
        static int Compute2(int i, int j)
        {
            return i - j;
        }
        static int Compute3(int i, int j)
        {
            return i * j;
        }
        static int Compute4(int i, int j)
        {
            return i / j;
        }    }
}
我已经想出...唉