请问怎么用treeview来生成一棵树呢?ACCESS数据库!

Question

表TB1
字段ID(文本),parentid(文本),name(文本),怎么动态加载生成树呢?谢谢

Answer 1

用来创建菜单吧?
add.subitem.add

Answer 2

现成的代码，参考一下吧，改一下表名和字段名即可
var
  List:TStringList;
  Node:TTreeNode;
  Index:Integer;
begin
  with Querydo
  begin
    Close;
    SQL.Clear;
    SQL.Text:='SELECT * FROM '+TableName+' ORDER BY PID,ID';
    Open;
  end;
  TreeView.Items.BeginUpdate;
  try
    TreeView.Items.Clear;    List:= TStringList.Create;
    try
      List.Sorted:= True;      while not Query.Eof do
      begin
        if Query.FieldByName('PID').AsInteger= 0 then 
        Node:= TreeView.Items.AddChild(nil, Query.FieldByName(mName).AsString)
        else
        begin
          Index:= List.IndexOf(Query.FieldByName('PID').AsString);
          Node:= TreeView.Items.AddChildFirst(TTreeNode(List.Objects[index]),
            Query.FieldByName(mName).AsString);
        end;
        List.AddObject(Query.FieldByName('ID').AsString, Node);
        Query.Next;
      end;
    finally
      List.Free;
    end;
  finally
    TreeView.Items.EndUpdate;
  end;

Answer 3

通过循环判断生成树就可以了文件夹图标好说，用imagelist就行，在添加节点时，将节点的imageindex设成imagelist中对应图标的序号就行

Answer 4

呵呵 上面那代码可以.不过加文件夹图标怎么加,lovelymelon能告诉加哪里吗?

Answer 5

放个ImageList加入图标
TreeView的Images指向ImageList1
通过代码设置ImageIndex,默认为0

Answer 6

价格ImageList，里面加载图片，然后treeview的Images指定为这个ImageListNode:= TreeView.Items.AddChildFirst(TTreeNode(List.Objects[index]),
            Query.FieldByName(mName).AsString);
Node.ImageIndex:=0;//这里加上这句

Answer 7

procedure TForm1.TreeView1Expanded(Sender: TObject; Node: TTreeNode);
begin
   node.ImageIndex:=1;
end;procedure TForm1.TreeView1Collapsed(Sender: TObject; Node: TTreeNode);
begin
  node.ImageIndex:=0;
end;

Answer 8

//添加同级文件夹
procedure TForm1.Button5Click(Sender: TObject);
var
  node:Ttreenode;
begin
  
  node:=self.TreeView1.Selected.Parent;
  node:=self.TreeView1.Items.AddChild(node,'fdfd') ;
  node.ImageIndex:=0;
end;
//添加下级文件夹
procedure TForm1.Button6Click(Sender: TObject);
var
  node:Ttreenode;
begin
  
  node:=Self.TreeView1.Selected;
  node:=Self.TreeView1.Items.AddChild(node,'fdsfsdf');end;
//删除
procedure TForm1.Button7Click(Sender: TObject);
begin
  self.TreeView1.Selected.Delete;
end;
//改名
procedure TForm1.Button8Click(Sender: TObject);
begin
  self.TreeView1.Selected.Text:='fsdfsdfds';
end;

Answer 9

数据库保存嘛，对于你的数据库结构不清楚，只能大略说添加同级文件夹和下级文件夹吧用insert into，修改就用update，删除就用delete关键是要考虑到其父节点，如果父节点不为空，就要考虑条件了 如where 地区=东北啥啥的
不知道你能不能明白

Answer 10

access数据库 表TB1
字段ID(文本),parentid(文本),name(文本) 就是这样的结构啊.另外还有个SORT字段不要也可以.

Answer 11

每个节点都有个DATA属性，就是数据库的ID字段值，修改哪个节点，就先取出来这个节点的DATA，在去数据库中修改ID=data数据行就行了，你应该补补基础知识了

Answer 12

ID         parentid     name          sort
1            0        工程文件夹           1
1.1          1           XX工程            0
1.1.1        1.1         OO段              0
1.2          1           YY工程            0就是这样啊,不会发图..

Answer 13

DATA是指针类型的吧?我要怎么才能取到他的值呢?

Answer 14

添加同级文件夹//添加同级文件夹
procedure TForm1.Button5Click(Sender: TObject);
var
  node,node1:Ttreenode;
begin
  node:=self.TreeView1.Selected.Parent;
  node1:=self.TreeView1.Items.AddChild(node,'fdfd') ;
  node1.ImageIndex:=0;
  if node=nil then
  begin
    m:=0;
    i:=self.TreeView1.Items.Count;
    for j:=0 to i-1 do
    begin
      if self.TreeView1.Items[j].Parent=nil then
        m:=m+1;
    end;
    self.adoquery1.close;
    self.adoquery1.connection:=self.adoconnection1;
    self.adoquery1.sql.clear;
    self.adoquery1.sql.add('insert into tablename (id,parent,name,sort) values(:s1,:s2,:s3,1)');
    self.ADOQuery1.Parameters.ParamByName('s1').Value:=inttostr(m+1);
    self.ADOQuery1.Parameters.ParamByName('s2').Value:=0;
    self.ADOQuery1.Parameters.ParamByName('s3').Value:='fdfd';
    self.adoquery1.ExecSQL
  end
  else
  begin
    i:=node.GetLastChild.Index+1;
    s:=node.text;
    self.adoquery1.close;
    self.adoquery1.connection:=self.adoconnection1;
    self.adoquery1.sql.clear;
    self.adoquery1.sql.add(select * from tablename where name=:s1');
    self.ADOQuery1.Parameters.ParamByName('s1').Value:=s;
    self.adoquery1.Open;
    bh:=self.adoquery1.fieldbyname('id').asstring;
    self.adoquery1.close;
    self.adoquery1.connection:=self.adoconnection1;
    self.adoquery1.sql.clear;
    self.adoquery1.sql.add('insert into tablename (id,parent,name,sort) values(:s1,:s2,:s3,1)');
    self.ADOQuery1.Parameters.ParamByName('s1').Value:=bh+'.'+inttostr(i);
    self.ADOQuery1.Parameters.ParamByName('s2').Value:=bh;
    self.ADOQuery1.Parameters.ParamByName('s3').Value:='fdfd';
    self.adoquery1.ExecSQL
  end;
end;

Answer 15

哎，空写代码太麻烦了添加下一级的数据库保存与添加同级的差不多//添加下级文件夹
procedure TForm1.Button5Click(Sender: TObject);
var
  node,node1:Ttreenode;
begin
  node:=self.TreeView1.Selected;
  node1:=self.TreeView1.Items.AddChild(node,'fdfd') ;
  node1.ImageIndex:=0;
  i:=node.GetLastChild.Index+1;
  s:=node.text;
  self.adoquery1.close;
  self.adoquery1.connection:=self.adoconnection1;
  self.adoquery1.sql.clear;
  self.adoquery1.sql.add(select * from tablename where name=:s1');
  self.ADOQuery1.Parameters.ParamByName('s1').Value:=s;
  self.adoquery1.Open;
  bh:=self.adoquery1.fieldbyname('id').asstring;
  self.adoquery1.close;
  self.adoquery1.connection:=self.adoconnection1;
  self.adoquery1.sql.clear;
  self.adoquery1.sql.add('insert into tablename (id,parent,name,sort) values(:s1,:s2,:s3,1)');
  self.ADOQuery1.Parameters.ParamByName('s1').Value:=bh+'.'+inttostr(i);
  self.ADOQuery1.Parameters.ParamByName('s2').Value:=bh;
  self.ADOQuery1.Parameters.ParamByName('s3').Value:='fdfd';
  self.adoquery1.ExecSQL
end;

Answer 16

删除//添加下级文件夹
procedure TForm1.Button5Click(Sender: TObject);
var
  node,node1:Ttreenode;
begin
  node1:=self.TreeView1.Selected;
  s:=node1.text;
  node:=node1.parent;
  if node=nil then
  begin
    i:=node1.index+1;
    self.adoquery1.close;
    self.adoquery1.connection:=self.adoconnection1;
    self.adoquery1.sql.clear;
    self.adoquery1.sql.add(delete from tablename where name=:s1 and id=:s2');
    self.ADOQuery1.Parameters.ParamByName('s1').Value:=s;
    self.ADOQuery1.Parameters.ParamByName('s2').Value:=inttostr(i);
    self.adoquery1.ExecSQL;
  end
  else
  begin
    s1:=node.text;
    self.adoquery1.close;
    self.adoquery1.connection:=self.adoconnection1;
    self.adoquery1.sql.clear;
    self.adoquery1.sql.add(select * from tablename where name=:s1 and parent=''0''');
    self.ADOQuery1.Parameters.ParamByName('s1').Value:=s1;
    self.adoquery1.Open;
    bh:=self.adoquery1.fieldbyname('id').asstring;    self.adoquery1.close;
    self.adoquery1.connection:=self.adoconnection1;
    self.adoquery1.sql.clear;
    self.adoquery1.sql.add(delete from tablename where name=:s1 and parent=:s2');
    self.ADOQuery1.Parameters.ParamByName('s1').Value:=s;
    self.ADOQuery1.Parameters.ParamByName('s2').Value:=bh;
    self.adoquery1.ExecSQL;  end;
end;

Answer 17

   lovelymelon,你这种写法是根据node1.text来从数据库中取唯一值ID,但是node1.text不一定是唯一值呢,所以从数据库中取出的ID有可能有多个,这样不都乱了吗?

Answer 18

如果text不是唯一的，就要在生成树的时候为每个节点创建一个data，里面包含此节点的id，在操作时，不取其text，而是取其data中的id值
给数节点添加data和读取data内容的参考代码如下，剩下的就简单了，你自己搞定吧unit Unit1;interfaceuses
  Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
  Dialogs, Grids, StdCtrls, Buttons, ComCtrls;
//定义一个树结构
type
  tmx=packed record
    bh:array[0..100] of string;//这个可以作为存放ID的字符串数组
end;
pmx=^tmx;
//**********************
type
  TForm1 = class(TForm)
    StringGrid1: TStringGrid;
    TreeView1: TTreeView;
    BitBtn1: TBitBtn;
    BitBtn2: TBitBtn;
    Label1: TLabel;
    Label2: TLabel;
    procedure FormShow(Sender: TObject);
    procedure StringGrid1SelectCell(Sender: TObject; ACol, ARow: Integer;
      var CanSelect: Boolean);
    procedure StringGrid1KeyPress(Sender: TObject; var Key: Char);
    procedure BitBtn1Click(Sender: TObject);
    procedure TreeView1MouseDown(Sender: TObject; Button: TMouseButton;
      Shift: TShiftState; X, Y: Integer);
  private
    { Private declarations }
  public
    { Public declarations }
  end;var
  Form1: TForm1;implementation{$R *.dfm}//添加节点，并为每个节点创建一个data
procedure TForm1.BitBtn1Click(Sender: TObject);
var
  p:pmx;
  tn:TTreeNode;
begin
  new(p);
  p.bh[0]:='010001';
  p.bh[1]:='010002';
  self.TreeView1.Items.Clear;
  tn:=self.TreeView1.Items.Add(nil,'1');//创建父节点
  //创建子节点，并为其关联一个结构体，123和234是节点的text
  self.TreeView1.Items.AddChildObject(tn,'123',p);
  self.TreeView1.Items.AddChildObject(tn,'234',p);
end;
//读取节点的data内容
procedure TForm1.TreeView1MouseDown(Sender: TObject; Button: TMouseButton;
  Shift: TShiftState; X, Y: Integer);
var
  tn:TTreeNode;
  s1,s2:string;
  i:Integer;
begin
  tn:=self.TreeView1.GetNodeAt(x,y);
  if tn=nil then
    Exit;
  if tn.Parent=nil then
    Exit;
  i:=tn.Index;
  s1:=pmx(tn.Data).bh[i];
  self.Label1.Caption:=s1;
  self.Label2.Caption:=s2;
end;

Answer 19

lovelymelon,能帮我改下吗/?我现在建树的过程是这样的!procedure TfrmManage.UpdateTreeView;
var
  List:TStringList;
  Node:TTreeNode;
  Index:Integer;
begin
  with DM.aqryManage   do
  begin
    Close;
    SQL.Clear;
    SQL.Text:='SELECT * FROM List ORDER BY ParentID,ID';
    Open;
  end;
  tvGCList.Items.BeginUpdate;
  try
    tvGCList.Items.Clear;    List:= TStringList.Create;
    try
      List.Sorted:= True;      while not DM.aqryManage.Eof do
      begin
        if DM.aqryManage.FieldByName('ParentID').AsString= '0' then
        begin
          Node:= tvGCList.Items.AddChild(nil, DM.aqryManage.FieldByName('mc').AsString);
          Node.ImageIndex:=0
        end
        else
        begin
          Index:= List.IndexOf(DM.aqryManage.FieldByName('ParentID').AsString);
          Node:= tvGCList.Items.AddChildFirst(TTreeNode(List.Objects[index]),
          DM.aqryManage.FieldByName('mc').AsString);
          Node.ImageIndex:=0
        end;
        List.AddObject(DM.aqryManage.FieldByName('ID').AsString, Node);
        DM.aqryManage.Next;
      end;
    finally
      List.Free;
    end;
  finally
    tvGCList.Items.EndUpdate;
  end;
end;

Answer 20

procedure TfrmManage.UpdateTreeView;
var
  List:TStringList;
  Node:TTreeNode;
  Index:Integer;
begin
  with DM.aqryManage   do
  begin
    Close;
    SQL.Clear;
    SQL.Text:='SELECT * FROM List ORDER BY ParentID,ID';
    Open;
  end;
  tvGCList.Items.BeginUpdate;
  try
    tvGCList.Items.Clear;    List:= TStringList.Create;
    try
      List.Sorted:= True;      while not DM.aqryManage.Eof do
      begin
        if DM.aqryManage.FieldByName('ParentID').AsString= '0' then
        begin
          Node:= tvGCList.Items.AddChild(nil, DM.aqryManage.FieldByName('mc').AsString);
          Node.ImageIndex:=0
        end
        else
        begin
          Index:= List.IndexOf(DM.aqryManage.FieldByName('ParentID').AsString);
          Node:= tvGCList.Items.AddChildFirst(TTreeNode(List.Objects[index]),
          DM.aqryManage.FieldByName('mc').AsString);
          Node.ImageIndex:=0
        end;
        List.AddObject(DM.aqryManage.FieldByName('ID').AsString, Node);
        DM.aqryManage.Next;
      end;
    finally
      List.Free;
    end;
  finally
    tvGCList.Items.EndUpdate;
  end;
end;

Answer 21

结合上面我给你那段代码，那里有结构体的定义，你试试procedure TfrmManage.UpdateTreeView;
var
  List:TStringList;
  Node:TTreeNode;
  Index,i:Integer;
  p:pmx;
  mc:string;
begin
  new(p);
  with DM.aqryManage   do
  begin
    Close;
    SQL.Clear;
    SQL.Text:='SELECT * FROM List ORDER BY ParentID,ID';
    Open;
  end;
  tvGCList.Items.BeginUpdate;
  try
    tvGCList.Items.Clear;    List:= TStringList.Create;
    try
      List.Sorted:= True;      while not DM.aqryManage.Eof do
      begin
        i:=DM.aqryManage.RecNo;
        s:=DM.aqryManage.FieldByName('ID').AsString;
        mc:=DM.aqryManage.FieldByName('mc').AsString;
        p.bh[i-1]:=s;
        if DM.aqryManage.FieldByName('ParentID').AsString= '0' then
        begin
          Node:= tvGCList.Items.AddChildObject(nil, mc,p);
          Node.ImageIndex:=0
        end
        else
        begin
          Index:= List.IndexOf(DM.aqryManage.FieldByName('ParentID').AsString);
          Node:= tvGCList.Items.AddChildObject(TTreeNode(List.Objects[index]),mc,p);
          Node.ImageIndex:=0
        end;
        List.AddObject(DM.aqryManage.FieldByName('ID').AsString, Node);
        DM.aqryManage.Next;
      end;
    finally
      List.Free;
    end;
  finally
    tvGCList.Items.EndUpdate;
  end;
end;

Answer 22

        i:=DM.aqryManage.RecNo;
        s:=DM.aqryManage.FieldByName('ID').AsString;
        mc:=DM.aqryManage.FieldByName('mc').AsString;
        p.bh[i-1]:=s;
这里运行的时候DM.aqryManage.RecNo=-1了,所以运行到p.bh[i-1]:=s就提示出错了,这是怎么回事呢?
提示

Answer 23

不可能吧，在循环里怎么会出现这种情况  DM.aqryManage.First;//加上这句试试
  while not DM.aqryManage.Eof do
  begin
    i:=DM.aqryManage.RecNo;
    s:=DM.aqryManage.FieldByName('ID').AsString;
    mc:=DM.aqryManage.FieldByName('mc').AsString;或者这样  i:=0;//
  while not DM.aqryManage.Eof do
  beign
    i:=i+1;
    s:=DM.aqryManage.FieldByName('ID').AsString;
    mc:=DM.aqryManage.FieldByName('mc').AsString;

Answer 24

这样生成的树用鼠标点击节点后显示的ID值与数据库里面ID值对不上号....

Answer 25

procedure TfrmManage.tvGCListClick(Sender: TObject);
var
  tn:TTreeNode;
  i:Integer;
  s1:string;
begin
  tn:=tvGCList.Selected;
  if tn=nil then
   Exit;
  if tn.Parent=nil then
    Exit;
  i:=tn.Index;
  s1:=pmx(tn.Data).bh[i];
  ShowMessage(s1);
end;

Answer 26

       
begin
  Index:= List.IndexOf(DM.aqryManage.FieldByName('ParentID').AsString);
  Node:= tvGCList.Items.AddChildObject(TTreeNode(List.Objects[index]),mc,p);
  Node.ImageIndex:=0
end;
可能是这段有问题

Answer 27

procedure TfrmManage.tvGCListClick(Sender: TObject);
var
  tn:TTreeNode;
  i:Integer;
  s1:string;
begin
  tn:=tvGCList.Selected;
  if tn=nil then
   Exit;
  if tn.Parent=nil then
    Exit;
  i:=tn.AbsoluteIndex;//这里改了试试，你那样去的index不对
  s1:=pmx(tn.Data).bh[i];
  ShowMessage(s1);
end;

Answer 28

生成树的代码改成这样，哎，直接在网页上写代码真是难啊procedure TfrmManage.UpdateTreeView;
var
  List,list1:TStrings;
  Node:TTreeNode;
  Index,i,m,n,k:Integer;
  p:pmx;
  mc:string;
begin
  new(p);
  with DM.aqryManage   do
  begin
    Close;
    SQL.Clear;
    SQL.Text:='SELECT * FROM List ORDER BY ParentID,ID';
    Open;
  end;
  tvGCList.Items.BeginUpdate;
  try
    tvGCList.Items.Clear;    List:= TStringList.Create;
    List.Clear;
    List1:= TStringList.Create;
    List1.Clear;    try
      
      while not DM.aqryManage.Eof do
      begin
        i:=DM.aqryManage.RecNo;
        s:=DM.aqryManage.FieldByName('ID').AsString;
        mc:=DM.aqryManage.FieldByName('mc').AsString;
        p.bh[i-1]:=s;
        if DM.aqryManage.FieldByName('ParentID').AsString= '0' then
        begin
          Node:= tvGCList.Items.AddChildObject(nil, mc,p);
          Node.ImageIndex:=0;
          k:=node.AbsoluteIndex;
          if list.index(s)=-1 then
          begin
            List.Add(s);
            list1.add(inttostr(k));
          end;
        end
        else
        begin
          Index:= List.IndexOf(DM.aqryManage.FieldByName('ParentID').AsString);
          k:=strtoint(list1.strings[index]);
          Node:= tvGCList.Items.AddChildObject(TTreeNode(k),mc,p);
          Node.ImageIndex:=0
        end;
        DM.aqryManage.Next;
      end;
    finally
      List.Free;
    end;
  finally
    tvGCList.Items.EndUpdate;
  end;
end;

Answer 29

靠，还是差了些东西，应该这样
靠，已经发三帖了，郁闷啊，等吧
我发给你的这个，你试了？还有什么问题？procedure TfrmManage.UpdateTreeView;
var
  List,list1:TStrings;
  Node:TTreeNode;
  Index,i,m,n,k:Integer;
  p:pmx;
  mc:string;
begin
  new(p);
  with DM.aqryManage   do
  begin
    Close;
    SQL.Clear;
    SQL.Text:='SELECT * FROM List ORDER BY ParentID,ID';
    Open;
  end;
  tvGCList.Items.BeginUpdate;
  try
    tvGCList.Items.Clear;    List:= TStringList.Create;
    List.Clear;
    List1:= TStringList.Create;
    List1.Clear;    try
      
      while not DM.aqryManage.Eof do
      begin
        i:=DM.aqryManage.RecNo;
        s:=DM.aqryManage.FieldByName('ID').AsString;
        mc:=DM.aqryManage.FieldByName('mc').AsString;
        p.bh[i-1]:=s;
        if DM.aqryManage.FieldByName('ParentID').AsString= '0' then
        begin
          Node:= tvGCList.Items.AddChildObject(nil, mc,p);
          Node.ImageIndex:=0;
          k:=node.AbsoluteIndex;
          if list.index(s)=-1 then
          begin
            List.Add(s);
            list1.add(inttostr(k));
          end;
        end
        else
        begin
          Index:= List.IndexOf(DM.aqryManage.FieldByName('ParentID').AsString);
          k:=strtoint(list1.strings[index]);
          Node:= tvGCList.Items.AddChildObject(TTreeNode(k),mc,p);
          Node.ImageIndex:=0;
          k:=node.AbsoluteIndex;
          if list.index(s)=-1 then
          begin
            List.Add(s);
            list1.add(inttostr(k));
          end;        end;
        DM.aqryManage.Next;
      end;
    finally
      List.Free;
    end;
  finally
    tvGCList.Items.EndUpdate;
  end;
end;

Answer 30

//添加同级文件夹
procedure TForm1.Button5Click(Sender: TObject);
var
  node,node1:Ttreenode;
begin
  node:=self.TreeView1.Selected.Parent;
  node1:=self.TreeView1.Items.AddChild(node,'fdfd') ;
  node1.ImageIndex:=0;
  if node=nil then
  begin
    m:=0;
    i:=self.TreeView1.Items.Count;
    for j:=0 to i-1 do
    begin
      if self.TreeView1.Items[j].Parent=nil then
        m:=m+1;
    end;
    self.adoquery1.close;
    self.adoquery1.connection:=self.adoconnection1;
    self.adoquery1.sql.clear;
    self.adoquery1.sql.add('insert into tablename (id,parent,name,sort) values(:s1,:s2,:s3,1)');
    self.ADOQuery1.Parameters.ParamByName('s1').Value:=inttostr(m+1);
    self.ADOQuery1.Parameters.ParamByName('s2').Value:=0;
    self.ADOQuery1.Parameters.ParamByName('s3').Value:='fdfd';
    self.adoquery1.ExecSQL
  end
  else
  begin
    i:=node.GetLastChild.Index+1;//得到i的值为6
    s:=node.text;
    self.adoquery1.close;
    self.adoquery1.connection:=self.adoconnection1;
    self.adoquery1.sql.clear;
    self.adoquery1.sql.add(select * from tablename where name=:s1');
    self.ADOQuery1.Parameters.ParamByName('s1').Value:=s;
    self.adoquery1.Open;
    bh:=self.adoquery1.fieldbyname('id').asstring;
    self.adoquery1.close;
    self.adoquery1.connection:=self.adoconnection1;
    self.adoquery1.sql.clear;
    self.adoquery1.sql.add('insert into tablename (id,parent,name,sort) values(:s1,:s2,:s3,1)');
    self.ADOQuery1.Parameters.ParamByName('s1').Value:=bh+'.'+inttostr(i);//**
    self.ADOQuery1.Parameters.ParamByName('s2').Value:=bh;
    self.ADOQuery1.Parameters.ParamByName('s3').Value:='fdfd';
    self.adoquery1.ExecSQL
  end;
end;
这段代码,如果我先在的ID是 1.1,1.2,1.3,1.6,1.7.因为我把1.6删掉了所以这样.
 i:=node.GetLastChild.Index+1;//得到i的值为6
最后
    self.ADOQuery1.Parameters.ParamByName('s1').Value:=bh+'.'+inttostr(i);//**
    self.ADOQuery1.Parameters.ParamByName('s2').Value:=bh;
    self.ADOQuery1.Parameters.ParamByName('s3').Value:='fdfd';
    self.adoquery1.ExecSQL
插入的时候s1就等于1.6了,这样和以前的ID重复了,ID是唯一的.

Answer 31

不加表和字段也行就是从表中查询某parentid下所有的id，然后得出最后一个.后的数字，最大的那个加1就是你现在的了
这个的确很麻烦

Answer 32

聪明，最后一个.前面的肯定是parentid，后面的就是顺序号了，取其最大值加1，然后组合起来就是新添加节点的id了