type
myclass1 = class
procedure xingming(var xingming:string);
procedure nianling(var nianling:integer);
end;procedure myclass1.xingming(xingming:string);
begin
xingming:='张三';
end;procedure myclass1.nianling(var nianling:integer);
begin
nianling:=18;
end;procedure TForm1.Button1Click(Sender: TObject);
var
mycls:myclass1;
name:string;
age:integer;
begin
mycls:=myclass1.Create;
mycls.xingming(name);
edit1.Text:=name;
end;end.
myclass1 = class
procedure xingming(var xingming:string);
procedure nianling(var nianling:integer);
end;procedure myclass1.xingming(xingming:string);
begin
xingming:='张三';
end;procedure myclass1.nianling(var nianling:integer);
begin
nianling:=18;
end;procedure TForm1.Button1Click(Sender: TObject);
var
mycls:myclass1;
name:string;
age:integer;
begin
mycls:=myclass1.Create;
mycls.xingming(name);
edit1.Text:=name;
end;end.
搞不懂这个程序做什么用的
上面这句话的意思是不是将name传入procedure myclass1.xingming(xingming:string);
这句看不懂
procedure myclass1.nianling(var nianling1: integer);
下边那个也是这样
我只是定义了方法
还有实现方法
怎么重名了?另外回四楼的
如果:mycls.xingming(name);就是传值的话那么
edit1.text:=name
内容就是:
procedure myclass1.xingming(xingming:string);
begin
xingming:='张三';
end; 上面这些也是我按照我学Java的思想弄的
如果错了 还请大家担待
没人教是在是难啊
procedure myclass1.nianling(var nianling: integer); 这俩个名字一样,随便改一个地方,让他们名字不同就可以了 比如下边,在变量后边加个1什么的
procedure myclass1.nianling(var nianling1: integer);
procedure myclass1.nianling(var nianling: integer);