发送的主题: 昂达发难卡菲倪反抗卡 收到的主题: ?gbk?B?urnKx7Cit6K3vcPmsLi3orC0yrEgICAgyP21yL2x?= =?gbk?B?v7S5/Q==?=
解码后的主题: ?燄昂达发难卡菲倪反抗卡function FindInTable(CSource:char):integer;
begin
result:=Pos(string(CSource),BaseTable)-1;
end;function DecodeBase64(Source:string):string;
var
SrcLen,Times,i:integer;
x1,x2,x3,x4,xt:byte;
begin
result:='';
SrcLen:=Length(Source);
Times:=SrcLen div 4;
for i:=0 to Times-1 do
begin
x1:=FindInTable(Source[1+i*4]);
x2:=FindInTable(Source[2+i*4]);
x3:=FindInTable(Source[3+i*4]);
x4:=FindInTable(Source[4+i*4]);
x1:=x1 shl 2;
xt:=x2 shr 4;
x1:=x1 or xt;
x2:=x2 shl 4;
result:=result+chr(x1);
if x3= 64 then break;
xt:=x3 shr 2;
x2:=x2 or xt;
x3:=x3 shl 6;
result:=result+chr(x2);
if x4=64 then break;
x3:=x3 or x4;
result:=result+chr(x3);
end;
end;
请教大家点解决啊
解码后的主题: ?燄昂达发难卡菲倪反抗卡function FindInTable(CSource:char):integer;
begin
result:=Pos(string(CSource),BaseTable)-1;
end;function DecodeBase64(Source:string):string;
var
SrcLen,Times,i:integer;
x1,x2,x3,x4,xt:byte;
begin
result:='';
SrcLen:=Length(Source);
Times:=SrcLen div 4;
for i:=0 to Times-1 do
begin
x1:=FindInTable(Source[1+i*4]);
x2:=FindInTable(Source[2+i*4]);
x3:=FindInTable(Source[3+i*4]);
x4:=FindInTable(Source[4+i*4]);
x1:=x1 shl 2;
xt:=x2 shr 4;
x1:=x1 or xt;
x2:=x2 shl 4;
result:=result+chr(x1);
if x3= 64 then break;
xt:=x3 shr 2;
x2:=x2 or xt;
x3:=x3 shl 6;
result:=result+chr(x2);
if x4=64 then break;
x3:=x3 or x4;
result:=result+chr(x3);
end;
end;
请教大家点解决啊
=?gbk?B?urnKx7Cit6K3vcPmsLi3orC0yrEgICAgyP21yL2x?= =?gbk?B?v7S5/Q==?=
去掉?gbk?B?假设发出的是汗是阿发方面案发按时 三等奖看过收到的编码 =?gbk?B?urnKx7Cit6K3vcPmsLi3orC0yrEgICAgyP21yL2x?= =?gbk?B?v7S5/Q==?=
解码后得到的却是 汗是阿发方面案发按时 三等奖?还有如何判断是不是这种编码,不是就不解码
Windows, SysUtils, StrUtils; Function GetMailTitle(Const Value: String): String;
Function GetMailSender(Const value: String):String; const cBase64:string='ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/';
implementationFunction QuotedPrintableEncode(mSource: String): String;
Var
I, J: Integer;
Begin
Result := '';
J := 0;
For I := 1 To Length(mSource) Do Begin
If mSource[I] In [#32..#127, #13, #10] - ['='] Then Begin
Result := Result + mSource[I];
Inc(J);
End Else Begin
Result := Result + '=' + IntToHex(Ord(mSource[I]), 2);
Inc(J, 3);
End;
If mSource[I] In [#13, #10] Then J := 0;
If J >= 70 Then Begin
Result := Result + #13#10;
J := 0;
End;
End;
End; { QuotedPrintableEncode }Function QuotedPrintableDecode(mCode: String): String;
Var
I, J, L: Integer;
Begin
Result := '';
J := 0;
mCode := AdjustLineBreaks(mCode);
L := Length(mCode);
I := 1;
While I <= L Do Begin
If mCode[I] = '=' Then Begin
Result := Result + Chr(StrToIntDef('$' + Copy(mCode, I + 1, 2), 0));
Inc(J, 3);
Inc(I, 3);
End Else If mCode[I] In [#13, #10] Then Begin
If J < 70 Then Result := Result + mCode[I];
If mCode[I] = #10 Then J := 0;
Inc(I);
End Else Begin
Result := Result + mCode[I];
Inc(J);
Inc(I);
End;
End;
End; { QuotedPrintableDecode }Function Base64Encode(mSource: String; mAddLine: Boolean = True): String;
Var
I, J: Integer;
S: String;
Begin
Result := '';
J := 0;
For I := 0 To Length(mSource) Div 3 - 1 Do Begin
S := Copy(mSource, I * 3 + 1, 3);
Result := Result + cBase64[Ord(S[1]) Shr 2 + 1];
Result := Result + cBase64[((Ord(S[1]) And $03) Shl 4) + (Ord(S[2]) Shr 4) + 1];
Result := Result + cBase64[((Ord(S[2]) And $0F) Shl 2) + (Ord(S[3]) Shr 6) + 1];
Result := Result + cBase64[Ord(S[3]) And $3F + 1];
If mAddLine Then Begin
Inc(J, 4);
If J >= 76 Then Begin
Result := Result + #13#10;
J := 0;
End;
End;
End;
I := Length(mSource) Div 3;
S := Copy(mSource, I * 3 + 1, 3);
Case Length(S) Of
1: Begin
Result := Result + cBase64[Ord(S[1]) Shr 2 + 1];
Result := Result + cBase64[(Ord(S[1]) And $03) Shl 4 + 1];
Result := Result + cBase64[65];
Result := Result + cBase64[65];
End;
2: Begin
Result := Result + cBase64[Ord(S[1]) Shr 2 + 1];
Result := Result + cBase64[((Ord(S[1]) And $03) Shl 4) + (Ord(S[2]) Shr 4) + 1];
Result := Result + cBase64[(Ord(S[2]) And $0F) Shl 2 + 1];
Result := Result + cBase64[65];
End;
End;
End; { Base64Encode }Function Base64Decode(mCode: String): String;
Var
I, L: Integer;
S: String;
Begin
Result := '';
L := Length(mCode);
I := 1;
While I <= L Do Begin
If Pos(mCode[I], cBase64) > 0 Then Begin
S := Copy(mCode, I, 4);
If (Length(S) = 4) Then Begin
Result := Result + Chr((Pos(S[1], cBase64) - 1) Shl 2 +
(Pos(S[2], cBase64) - 1) Shr 4);
If S[3] <> cBase64[65] Then Begin
Result := Result + Chr(((Pos(S[2], cBase64) - 1) And $0F) Shl 4 +
(Pos(S[3], cBase64) - 1) Shr 2);
If S[4] <> cBase64[65] Then
Result := Result + Chr(((Pos(S[3], cBase64) - 1) And $03) Shl 6 +
(Pos(S[4], cBase64) - 1));
End;
End;
Inc(I, 4);
End Else Inc(I);
End;
End; { Base64Decode }Function GetMailTitle(Const Value: String): String;
Var
iPos: integer;
Begin
Result := Value;
If Copy(Value, 1, 2) <> '=?' Then
Begin
Result := Value;
exit;
End;
//'?B?'前面的都要去掉
iPos := Pos('?B?', Value);
If iPos = 0 Then
Begin
iPos := Pos('?Q?', Value);
If iPos = 0 Then
Begin
Result := Value;
exit;
End;
Inc(iPos, 3);
//最后的'?='也要去掉
Result := Copy(Value, iPos, Length(Value) - iPos - 1);
Result := QuotedPrintableDecode(Result);
End
Else
Begin
Inc(iPos, 3);
//最后的'?='也要去掉
Result := Copy(Value, iPos, Length(Value) - iPos - 1);
Result := Base64Decode(Result);
End;End;
//由于发件人是中文+'<[email protected]>',组成的,所以多加了这个函数!
Function GetMailSender(Const value: String):String;
var
iPos:integer;
preStr:String;
bkStr:String;
begin
Result:= value;
If Copy(Value, 1, 2) <> '=?' Then
Begin
Result := Value;
exit;
End;
iPos := Pos('?= <', Value);
if iPos=0 then
begin
Result := Value;
exit;
end
else
begin
preStr:=Copy(Value,1,iPos+1);
bkStr:=Copy(Value,iPos+2,length(Value)-iPos+2);
Result:= GetMailTitle(preStr)+ bkStr;
end;
end;end.
前後是對應的。有點類似於XML的操作 <node> content </node> 因此後面的也要去掉 ==? = . 你可翠直接對你發的文字BASE64後看編碼與你接受的BASE64編碼對比下,就會發現,頭與尾都有一個編碼的節點
大虾快出现