各位,问个初级的问题:
如何将Memo3.Text中的FF55030405060708AA00000000000000323C463202900266029A01(十六进制)转换成整形数组:a[0]:=0xFF,a[2]:=0x55,a[3]:=0x03..... 一定是要变成整形数据。谢谢!
如何将Memo3.Text中的FF55030405060708AA00000000000000323C463202900266029A01(十六进制)转换成整形数组:a[0]:=0xFF,a[2]:=0x55,a[3]:=0x03..... 一定是要变成整形数据。谢谢!
i,n:integer;
begin
with Memo1 do
begin
Text:='FF 55 03 04 05 06 07 08 AA 00 00 00 00 00 00 00 32 3C 46 32 02 90 02 66 02 9A 01';
Text:=StringReplace(Text,' ','',[rfReplaceAll]);//没空格就不要这句了
n:=Length(Text);
SetLength(a,n div 2);
for i:=0 to (n div 2)-1 do
a[i]:=StrToInt('$'+Text[(i+1)*2-1]+Text[(i+1)*2]);
end;
end;
procedure TForm1.Button1Click(Sender: TObject);
var
s:string;
t:array [0..255] of char;
a:array [0..255] of integer;
i:integer;
begin
s:='FF55030405060708AA00000000000000323C463202900266029A01';
hextobin(pchar(s),@t,length(s) div 2);
for i:=0 to length(s) div 2-1 do
a[i]:=integer(t[i]);
end;