字符串移位加密???
例如:str:=FBKMZ542
用DELPHI 加密,实现字符简单移位
例如通过如下方式加密:
s:='FBKMZ542';
for i:=1 to length(s) do
begin
s[i]:=chr(ord(s[i])xor 250);
end;
或:只对字符进行加3减3操作或者:
for i:=1 to length(s) do
begin
s[i]:=chr(ord(s[i])shl 2);
end;最好用后者加密!
关键是要用VBscript脚本解密???
例如:str:=FBKMZ542
用DELPHI 加密,实现字符简单移位
例如通过如下方式加密:
s:='FBKMZ542';
for i:=1 to length(s) do
begin
s[i]:=chr(ord(s[i])xor 250);
end;
或:只对字符进行加3减3操作或者:
for i:=1 to length(s) do
begin
s[i]:=chr(ord(s[i])shl 2);
end;最好用后者加密!
关键是要用VBscript脚本解密???
var
Source_Len,Len : integer;
Count,c : integer;
a1,a2 : byte;
ind : dword;
Encode_Str : string;
begin
Result := '';
Encode_Str := '';
Len := 0;
a1 := 0;
a2 := 0;
c := 0;
ind := 0;
Count := 0;
Source_Len := Length(source);
while Count < Source_Len do
begin
if Len >= $2710 then
break;
ind := ord(source[Count+1]);
ind := ind shr (c+2);
a1 := ind or a2;
a1 := a1 and $3f;
ind := ord(source[Count+1]);
ind := ind shl (8-(c+2));
ind := ind shr 2;
a2 := ind and $3f;
inc(c,2);
if c >= 6 then
begin
if Len >= $270f then
begin
Encode_Str := Encode_Str + chr(a1 + $3c);
inc(Len);
end
else
begin
Encode_Str := Encode_Str + chr(a1 + $3c);
Encode_Str := Encode_Str + chr(a2 + $3c);
Inc(Len,2);
end;
c := 0;
a2 := 0;
end
else
begin
Encode_Str := Encode_Str + chr(a1 + $3c);
Inc(Len);
end;
inc(Count);
end;
if c > 0 then
begin
Encode_Str := Encode_Str + chr(a2 + $3c);
Inc(Len);
end;
SetLength(Encode_Str,Len);
Result := Encode_Str;
end;
function Decode(source : string):string; //解密
var
Source_Len,Len : integer;
Count,c1,c2 : integer;
code : array[0..7] of byte;
a1,a2 : byte;
ind : dword;
Decode_Str : string;
label L1,L2;
begin
Result := '';
Decode_Str := '';
code[2] := $fc;
code[4] := $f0;
code[6] := $c0;
Len := 0;
a1 := 0;
a2 := 0;
c1 := 2;
c2 := 0;
ind := 0;
Count := 0;
Source_Len := Length(source);
while (Count < Source_Len) do
begin
if(ord(Source[Count+1]) - $3c) < 0 then
begin
Decode_Str := Decode_Str + Source[Count+1];
inc(Len);
inc(Count);
a1 := 0;
a2 := 0;
c1 := 2;
c2 := 0;
ind := 0;
Continue;
//break;
end;
a1 := ord(Source[Count+1]) - $3c;
if Len >= Source_Len then
begin
break;
end;
if (c2 + 6) < 8 then
begin
goto L2;
end;
ind := a1 and $3f;
ind := ind shr (6-c1);
Decode_Str := Decode_Str + chr(ind or a2);
Inc(Len);
c2 := 0;
if c1 >= 6 then
begin
c1 := 2;
goto L1;
end;
inc(c1,2);
L2 :a2 := a1 shl c1;
a2 := a2 and code[c1];
c2 := c2 + (8 - c1);
L1 :inc(count);
end;
SetLength(Decode_Str,Len);
Result := Decode_Str;
end;
var
s:string;
i:integer;
begin
s:=Edit1.Text;
for i:=1 to length(s) do
begin
s[i]:=chr( ord(s[i]) xor 250);
end;
Label1.Caption:=s;
end;
加密和解密一样的函数。
/////////////////////////////////////////
procedure TForm1.Button2Click(Sender: TObject);
var
s:string;
i:integer;
begin
s:=Label1.Caption;
for i:=1 to length(s) do
begin
s[i]:=chr(ord(s[i]) xor 250);
end;
Label2.Caption:=s;
end;
〈%dim sequence
sequence=Request("sequence")
for i=0 to len(sequence)-1)
sequence(i)=chr(Asc(sequence(i) xor 250);
next
%〉
请问这么做错在哪里???
sequence(i)=chr(Asc(sequence(i) xor 250); '多了一个;