我用
var
i:integer;
viewstring:string;
rbuf,sbuf:array[1..1024] of byte;
begin
viewstring:='';
move(buffer^,pchar(@rbuf)^,bufferlength);
for i:=1 to bufferlength do
viewstring:=viewstring+inttohex(rbuf[i],2)+' ';
end;
得到十六进制数,如何转换为十进制数?急急!
var
i:integer;
viewstring:string;
rbuf,sbuf:array[1..1024] of byte;
begin
viewstring:='';
move(buffer^,pchar(@rbuf)^,bufferlength);
for i:=1 to bufferlength do
viewstring:=viewstring+inttohex(rbuf[i],2)+' ';
end;
得到十六进制数,如何转换为十进制数?急急!
就可以得到十六进制AB的十进制值。
procedure TForm1.Comm1ReceiveData(Sender: TObject; Buffer: Pointer;
BufferLength: Word);
var
i:integer;
Hex:integer;
viewstring:string;
rbuf,sbuf:array[1..1024] of byte;
begin
viewstring:='';
move(buffer^,pchar(@rbuf)^,bufferlength);
for i:=1 to bufferlength do
viewstring:=viewstring+inttohex(rbuf[i],2)+' ';
viewstring:='接受'+viewstring;
memo1.lines.add(viewstring);
Hex:=Hextoint(viewstring);
memo2.Lines.add(inttostr(Hex));
end;
可是不行,请指导,谢谢!!
a*10 + b*10 +……+ c*10