按惯例应使用10个数字加25个字母 0 1 2 3 4 5 6 7 8 9 A .... Y 10就是A,15就是F .... 35 应用 10
(*// 标题:无限进制转换 说明:使用于数学领域进制之间相互转换 设计:Zswang 日期:2002-01-24 支持:[email protected] //*)///////Begin Source const cScaleChar = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ';function IntPower(Base, Exponent: Integer): Int64; { 返回Base的Exponent次方 } var I: Integer; begin Result := 1; for I := 1 to Exponent do Result := Result * Base; end; { IntPower }function IntToDigit(mNumber: Int64; mScale: Byte; mLength: Integer = 0): string; { 返回整数的进制表示;mScale指定多少进制;mLength指定长度,长度不足时向前补0 } var I, J: Int64; K: Integer; begin Result := ''; I := mNumber; while (I >= mScale) and (mScale > 1) do begin J := I mod mScale; I := I div mScale; Result := cScaleChar[J + 1] + Result; end; Result := cScaleChar[I + 1] + Result; for K := 1 to mLength - Length(Result) do Result := '0' + Result; end; { IntToDigit }function DigitToInt(mDigit: string; mScale: Byte): Int64; { 返回进制表示转换成整数;mScale指定多少进制 } var I: Byte; L: Integer; begin Result := 0; mDigit := UpperCase(mDigit); L := Length(mDigit); for I := 1 to L do Result := Result + (Pos(mDigit[L - I + 1], cScaleChar) - 1) * IntPower(mScale, I - 1); end; { DigitToInt } ///////End Source///////Begin Demo procedure TForm1.Button1Click(Sender: TObject); begin Edit1.Text := IntToDigit(StrToInt64Def(Edit2.Text, 0), 35); end;procedure TForm1.Button2Click(Sender: TObject); begin Edit2.Text := IntToStr(DigitToInt(Edit1.Text, 35)); end; ///////End Demo注意,最大数值为十进制的“9223372036854775807”(三十五进制的“2PIJMIKEXRXP7”)~~
procedure TForm1.Button1Click(Sender: TObject); var r,m,y:integer; begin y:=strtoint(edit1.text); m:=y mod 35; r:=(y div 35)*10+m; edit2.Text:=inttostr(r); end;
a = a div 35 就是高位不停循环 直到 a div 35 =0
abcd?下面是思路对35 mod,得到的结果再被35 mod,直到结束,为止
比如:
xxxx mod 35 = a
(xxxx mod 35) mod 35 = b
……则结果为 ……ba
>>(xxxx mod 35) mod 35 = b(xxxx div 35) mod 35 = b
16就是G.......35就是Z.这样来表示怎么样来实现呢?
标题:无限进制转换
说明:使用于数学领域进制之间相互转换
设计:Zswang
日期:2002-01-24
支持:[email protected]
//*)///////Begin Source
const
cScaleChar = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ';function IntPower(Base, Exponent: Integer): Int64; { 返回Base的Exponent次方 }
var
I: Integer;
begin
Result := 1;
for I := 1 to Exponent do
Result := Result * Base;
end; { IntPower }function IntToDigit(mNumber: Int64; mScale: Byte;
mLength: Integer = 0): string;
{ 返回整数的进制表示;mScale指定多少进制;mLength指定长度,长度不足时向前补0 }
var
I, J: Int64;
K: Integer;
begin
Result := '';
I := mNumber;
while (I >= mScale) and (mScale > 1) do begin
J := I mod mScale;
I := I div mScale;
Result := cScaleChar[J + 1] + Result;
end;
Result := cScaleChar[I + 1] + Result;
for K := 1 to mLength - Length(Result) do Result := '0' + Result;
end; { IntToDigit }function DigitToInt(mDigit: string; mScale: Byte): Int64;
{ 返回进制表示转换成整数;mScale指定多少进制 }
var
I: Byte;
L: Integer;
begin
Result := 0;
mDigit := UpperCase(mDigit);
L := Length(mDigit);
for I := 1 to L do
Result := Result + (Pos(mDigit[L - I + 1], cScaleChar) - 1) *
IntPower(mScale, I - 1);
end; { DigitToInt }
///////End Source///////Begin Demo
procedure TForm1.Button1Click(Sender: TObject);
begin
Edit1.Text := IntToDigit(StrToInt64Def(Edit2.Text, 0), 35);
end;procedure TForm1.Button2Click(Sender: TObject);
begin
Edit2.Text := IntToStr(DigitToInt(Edit1.Text, 35));
end;
///////End Demo注意,最大数值为十进制的“9223372036854775807”(三十五进制的“2PIJMIKEXRXP7”)~~
var
r,m,y:integer;
begin
y:=strtoint(edit1.text);
m:=y mod 35;
r:=(y div 35)*10+m;
edit2.Text:=inttostr(r);
end;