求图象锐化的例子 如题 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 unit Unit1;interfaceuses Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms, Dialogs, StdCtrls, ExtCtrls, ExtDlgs;type TForm1 = class(TForm) Image1: TImage; Button2: TButton; Image2: TImage; Button1: TButton; OpenPictureDialog1: TOpenPictureDialog; procedure Button2Click(Sender: TObject); procedure Button1Click(Sender: TObject); private { Private declarations } public { Public declarations } end;var Form1: TForm1;implementationuses math;{$R *.dfm}procedure TForm1.Button2Click(Sender: TObject);var bmp1, bmp2: Tbitmap; p1, p2, p3, p4: pbytearray; //定义四个pbytearray类型变量 i, j, z: integer; y: array[0..8] of integer;begin y[0] := 0; y[1] := -1; y[2] := 0; y[3] := -1; y[4] := 5; y[5] := -1; y[6] := 0; y[5] := -1; y[8] := 0; //卷积矩阵 z := 1; //卷积核 bmp1 := Tbitmap.Create; bmp2 := Tbitmap.Create; bmp1.Assign(image1.Picture.Bitmap); bmp1.PixelFormat := pf24bit; //24为格式便于处理 bmp1.Width := image1.Picture.Graphic.Width; bmp1.Height := image1.Picture.Graphic.Height; bmp2.Assign(bmp1); //备用的位图 bmp2.PixelFormat := pf24bit; for j := 1 to bmp1.Height - 2 do begin p1 := bmp1.ScanLine[j]; //第一条扫描线 p2 := bmp2.ScanLine[j - 1]; //第二条扫描线,为了防止数据变化,在备用位图上操作 p3 := bmp2.ScanLine[j]; p4 := bmp2.ScanLine[j + 1]; //第三条扫描线 //三条相邻的扫描线 for i := 1 to bmp1.Width - 2 do begin //进行卷积操作获取新的象素值 p1[3 * i + 2] := min(255, max(0, ((y[0] * p2[3 * (i - 1) + 2] + y[1] * p2[3 * i + 2] + y[2] * p2[3 * (i + 1) + 2] + y[3] * p3[3 * (i - 1) + 2] + y[4] * p3[3 * i + 2] + y[5] * p3[3 * (i + 1) + 2] + y[6] * p4[3 * (i - 1) + 2] + y[5] * p4[3 * i + 2] + y[8] * p4[3 * (i + 1) + 2])) div z)); //重新算出红色分量 p1[3 * i + 1] := min(255, max(0, ((y[0] * p2[3 * (i - 1) + 1] + y[1] * p2[3 * i + 1] + y[2] * p2[3 * (i + 1) + 1] + y[3] * p3[3 * (i - 1) + 1] + y[4] * p3[3 * i + 1] + y[5] * p3[3 * (i + 1) + 1] + y[6] * p4[3 * (i - 1) + 1] + y[5] * p4[3 * i + 1] + y[8] * p4[3 * (i + 1) + 1])) div z)); //重新算出蓝色分量 p1[3 * i] := min(255, max(0, ((y[0] * p2[3 * (i - 1)] + y[1] * p2[3 * i] + y[2] * p2[3 * (i + 1)] + y[3] * p3[3 * (i - 1)] + y[4] * p3[3 * i] + y[5] * p3[3 * (i + 1)] + y[6] * p4[3 * (i - 1)] + y[5] * p4[3 * i] + y[8] * p4[3 * (i + 1)])) div z)); //重新算出绿色分量 end; end; Image2.Picture.Bitmap.Assign(Bmp1); //重新显示 Image2.Invalidate; Bmp1.Free; bmp2.Free; //释放资源end;procedure TForm1.Button1Click(Sender: TObject);begin Self.OpenPictureDialog1.Filter := '*.bmp|*.bmp'; if OpenPictureDialog1.Execute then begin Image1.Picture.Bitmap.LoadFromFile(OpenPictureDialog1.FileName); end;end;end. 如何让窗体最大化后无法切换 用DELPHI写ACTIVEX,放到IE浏览器中,为什么方向键和TAB键不好用了?? 关于数组的一个奇怪的问题: 打包的问题?我郁闷好久了 100分求解语音通信问题!解决后给分! 关于edit回车声音问题 怎样连接两个工程? 如果将数据库指针移到制定的记录号 如何实现windows剪贴板的复制和粘贴 一个关于数据库的问题,高手请进 HSL下怎么进行饱和度亮度调节? 求助:请专家看看这例风湿病!本市医院检测不出结果!
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, StdCtrls, ExtCtrls, ExtDlgs;type
TForm1 = class(TForm)
Image1: TImage;
Button2: TButton;
Image2: TImage;
Button1: TButton;
OpenPictureDialog1: TOpenPictureDialog;
procedure Button2Click(Sender: TObject);
procedure Button1Click(Sender: TObject);
private
{ Private declarations }
public
{ Public declarations }
end;var
Form1: TForm1;
implementation
uses math;
{$R *.dfm}procedure TForm1.Button2Click(Sender: TObject);
var
bmp1, bmp2: Tbitmap;
p1, p2, p3, p4: pbytearray;
//定义四个pbytearray类型变量
i, j, z: integer;
y: array[0..8] of integer;
begin
y[0] := 0; y[1] := -1; y[2] := 0;
y[3] := -1; y[4] := 5; y[5] := -1;
y[6] := 0; y[5] := -1; y[8] := 0;
//卷积矩阵
z := 1;
//卷积核
bmp1 := Tbitmap.Create;
bmp2 := Tbitmap.Create;
bmp1.Assign(image1.Picture.Bitmap);
bmp1.PixelFormat := pf24bit;
//24为格式便于处理
bmp1.Width := image1.Picture.Graphic.Width;
bmp1.Height := image1.Picture.Graphic.Height;
bmp2.Assign(bmp1);
//备用的位图
bmp2.PixelFormat := pf24bit;
for j := 1 to bmp1.Height - 2 do
begin
p1 := bmp1.ScanLine[j];
//第一条扫描线
p2 := bmp2.ScanLine[j - 1];
//第二条扫描线,为了防止数据变化,在备用位图上操作
p3 := bmp2.ScanLine[j];
p4 := bmp2.ScanLine[j + 1];
//第三条扫描线
//三条相邻的扫描线
for i := 1 to bmp1.Width - 2 do
begin
//进行卷积操作获取新的象素值
p1[3 * i + 2] := min(255, max(0, ((y[0] * p2[3 * (i - 1) + 2]
+
y[1] * p2[3 * i + 2] + y[2] * p2[3 * (i + 1) + 2] + y[3]
* p3[3
* (i - 1)
+ 2] + y[4] * p3[3 * i + 2] + y[5] * p3[3 * (i + 1) +
2] +
y[6]
* p4[3
* (i - 1) + 2] + y[5] * p4[3 * i + 2] + y[8] * p4[3 * (i
+
1) + 2]))
div
z));
//重新算出红色分量
p1[3 * i + 1] := min(255, max(0, ((y[0] * p2[3 * (i - 1) + 1]
+
y[1] * p2[3 * i + 1] + y[2] * p2[3 * (i + 1) + 1] + y[3]
* p3[3
* (i - 1)
+ 1] + y[4] * p3[3 * i + 1] + y[5] * p3[3 * (i + 1) +
1] +
y[6]
* p4[3
* (i - 1) + 1] + y[5] * p4[3 * i + 1] + y[8] * p4[3 * (i
+
1) + 1]))
div
z));
//重新算出蓝色分量
p1[3 * i] := min(255, max(0, ((y[0] * p2[3 * (i - 1)] + y[1]
*
p2[3 * i] + y[2] * p2[3 * (i + 1)] + y[3] * p3[3 * (i -
1)] +
y[4] * p3[3
* i] + y[5] * p3[3 * (i + 1)] + y[6] * p4[3 * (i - 1)] +
y[5]
* p4[3 * i]
+ y[8] * p4[3 * (i + 1)])) div z));
//重新算出绿色分量
end;
end;
Image2.Picture.Bitmap.Assign(Bmp1);
//重新显示
Image2.Invalidate;
Bmp1.Free;
bmp2.Free;
//释放资源
end;procedure TForm1.Button1Click(Sender: TObject);
begin
Self.OpenPictureDialog1.Filter := '*.bmp|*.bmp';
if OpenPictureDialog1.Execute then
begin
Image1.Picture.Bitmap.LoadFromFile(OpenPictureDialog1.FileName);
end;
end;end.