从一个定长128位的pchar(array[0..128] of byte;)类型的变量tt 将其通过如下变换:for i := 0 to 127 do
outstr1 := outstr1 + inttohex(ord(tt[i]),2);变成一个256位长的16进制串,可是现在想把这个16进制串还原成定长128位的pchar(类型同tt),却无法实现,我是这样转换的:var
Text, Buffer: PChar; //Buffer为得到的结果pchar
Bufsize : Integer;
--------------------
Text := pchar(Trim(Memo2.Text)); //Memo2.text为256位长的16进制串
BufSize := Length(Text) DIV 2;
HexToBin(Text, Buffer, BufSize);很奇怪,得到的Buffer的Length居然不是128位的,结果转换出来就是和tt不一样!!!这个问题我研究了2天就是无法搞定,请指教!!!!
outstr1 := outstr1 + inttohex(ord(tt[i]),2);变成一个256位长的16进制串,可是现在想把这个16进制串还原成定长128位的pchar(类型同tt),却无法实现,我是这样转换的:var
Text, Buffer: PChar; //Buffer为得到的结果pchar
Bufsize : Integer;
--------------------
Text := pchar(Trim(Memo2.Text)); //Memo2.text为256位长的16进制串
BufSize := Length(Text) DIV 2;
HexToBin(Text, Buffer, BufSize);很奇怪,得到的Buffer的Length居然不是128位的,结果转换出来就是和tt不一样!!!这个问题我研究了2天就是无法搞定,请指教!!!!
{ 函数 : RESULTSTRING = HexToBin(HEXSTRING)
{ 目的 : 把十六进制字符串转换为二进制字符串
{
{===============================================================}
{ 函数 : RESULTINTEGER = HexCharToInt(HEXCHAR)
{ 目的 : 转换一个十六进制字符为整数
{===============================================================}
{ 函数 : RESULTSTRING = HexCharToBin(HEXCHAR)
{ 目的 : 转换一个十六进制字符为二进制字符串
{===============================================================}
{ 函数 : RESULTINTEGER = Pow(BASE,POWER)
{ 目的 : 指数函数
{===============================================================}
{ 函数 : RESULTINTEGER = BinStrToInt(BINSTRING)
{ 目的 : 把二进制字符串转换为整数
{===============================================================}
{ 函数 : RESULTSTRING = DecodeSMS7Bit (PDUSTRING)
{ 目的 : 解码一个7-bit SMS (GSM 03.38) 为ASCII码
{===============================================================}
{ 函数 : RESULTSTRING = ReverseStr (SOURCESTRING)
{ 目的 : 反转一个字符串
{===============================================================}
unit BinHexTools;
interface function HexToBin(HexNr : string): string;
function HexCharToInt(HexToken : char):Integer;
function HexCharToBin(HexToken : char): string;
function pow(base, power: integer): integer;
function BinStrToInt(BinStr : string) : integer;
function DecodeSMS7Bit(PDU : string):string;
function ReverseStr(SourceStr : string) : string; implementation uses sysutils, dialogs; function HexCharToInt(HexToken : char):Integer;
begin
{if HexToken>#97 then HexToken:=Chr(Ord(HexToken)-32);
{ use lowercase aswell } Result:=0; if (HexToken>#47) and (HexToken<#58) then { chars 0....9 }
Result:=Ord(HexToken)-48
else if (HexToken>#64) and (HexToken<#71) then { chars A....F }
Result:=Ord(HexToken)-65 + 10;
end; function HexCharToBin(HexToken : char): string;
var DivLeft : integer;
begin
DivLeft:=HexCharToInt(HexToken); { first HEX->BIN }
Result:='';
{ Use reverse dividing }
repeat { Trick; divide by 2 }
if odd(DivLeft) then { result = odd ? then bit = 1 }
Result:='1'+Result { result = even ? then bit = 0 }
else
Result:='0'+Result; DivLeft:=DivLeft div 2; { keep dividing till 0 left and length = 4 }
until (DivLeft=0) and (length(Result)=4); { 1 token = nibble = 4 bits }
end; function HexToBin(HexNr : string): string;
{ only stringsize is limit of binnr }
var Counter : integer;
begin
Result:=''; for Counter:=1 to length(HexNr) do
Result:=Result+HexCharToBin(HexNr[Counter]);
end; function pow(base, power: integer): integer;
var counter : integer;
begin
Result:=1; for counter:=1 to power do
Result:=Result*base;
end; function BinStrToInt(BinStr : string) : integer;
var counter : integer;
begin
if length(BinStr)>16 then
raise ERangeError.Create(#13+BinStr+#13+
'is not within the valid range of a 16 bit binary.'+#13); Result:=0; for counter:=1 to length(BinStr) do
if BinStr[Counter]='1' then
Result:=Result+pow(2,length(BinStr)-counter);
end; function DecodeSMS7Bit(PDU : string):string;
var OctetStr : string;
OctetBin : string;
Charbin : string;
PrevOctet: string;
Counter : integer;
Counter2 : integer;
begin
PrevOctet:='';
Result:=''; for Counter:=1 to length(PDU) do
begin
if length(PrevOctet)>=7 then { if 7 Bit overflow on previous }
begin
if BinStrToInt(PrevOctet)<>0 then
Result:=Result+Chr(BinStrToInt(PrevOctet))
else Result:=Result+' '; PrevOctet:='';
end; if Odd(Counter) then { only take two nibbles at a time }
begin
OctetStr:=Copy(PDU,Counter,2);
OctetBin:=HexToBin(OctetStr); Charbin:='';
for Counter2:=1 to length(PrevOctet) do
Charbin:=Charbin+PrevOctet[Counter2]; for Counter2:=1 to 7-length(PrevOctet) do
Charbin:=OctetBin[8-Counter2+1]+Charbin; if BinStrToInt(Charbin)<>0 then Result:=Result+Chr(BinStrToInt(CharBin))
else Result:=Result+' '; PrevOctet:=Copy(OctetBin,1,length(PrevOctet)+1);
end;
end;
end; function ReverseStr(SourceStr : string) : string;
var Counter : integer;
begin
Result:=''; for Counter:=1 to length(SourceStr) do
Result:=SourceStr[Counter]+Result;
end; end.
当然不行了,你那样的话取的值就不对
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那究竟要如何转换回来呢? 应该会有办法转换回来的吧!