RT

解决方案 »

  1.   

    知己写一个函数
    截取-转化进制-转化string,应当很简单
      

  2.   

    我找不到好办法,你先凑合着用吧!
    var buf:array[0..5] of byte;
        test:array[0..5] of integer;
        i:integer;
        s:string;
    begin
    buf[0]:=$03;
    buf[1]:=$06;
    buf[2]:=$0C;
    buf[3]:=$0E;
    buf[4]:=$28;
    buf[5]:=$10;
    for i:=0 to 5 do
    begin
    test[i]:=(buf[i]);
    if (i=3) or (i=4) then
    s:=s+inttostr(test[i])+':' else
    if i=5 then
    s:=s+inttostr(test[i]) else
    s:=s+inttostr(test[i])+'-';
    end;
    showmessage(s);
    end;
      

  3.   

    比刚才的哪个简单点!
    var buf:array[0..5] of byte;
        s:String;
        i:integer;
        t:Tdatetime;
    begin
    buf[0]:=$03;
    buf[1]:=$06;
    buf[2]:=$0C;
    buf[3]:=$0E;
    buf[4]:=$28;
    buf[5]:=$10;
    t:=StrToDateTime(IntToStr(buf[0])+'-'+IntToStr(buf[1])+'-'+IntToStr(buf[2])+
    ' '+IntToStr(buf[3])+':'+IntToStr(buf[4])+':'+IntToStr(buf[5]));
    ShowMessage(datetimetostr(t));
    end;