两端点为(x1,y1),(x2,y2),弧度为npi:=3.14;
m:=180*n/3.14; //角度
l1:=Sqrt(sqr(x1-x2)+sqr(y1-y2))/2;
l2:=l1/Sin(m/2);
l3:=sqrt(sqr(l2)-sqr(l1));
tx:=l3*Sin(m/2);
ty:=13*Cos(m/2);
x:=(x1+x2)/2+tx;
y:=(y1+y2)/2+ty;
//两解,还可以减tx,ty!
m:=180*n/3.14; //角度
l1:=Sqrt(sqr(x1-x2)+sqr(y1-y2))/2;
l2:=l1/Sin(m/2);
l3:=sqrt(sqr(l2)-sqr(l1));
tx:=l3*Sin(m/2);
ty:=13*Cos(m/2);
x:=(x1+x2)/2+tx;
y:=(y1+y2)/2+ty;
//两解,还可以减tx,ty!
Xc=0.5*(x1+x2)+0.5*(y1-y2)*(1-cos(β/2))/sin(β/2)
Yc=0.5*(y1+y2)+0.5*(x2-x1)*(1-cos(β/2))/sin(β/2)
解2:
Xc=0.5*(x1+x2)+0.5*(y2-y1)*(1-cos(β/2))/sin(β/2)
Yc=0.5*(y1+y2)+0.5*(x1-x2)*(1-cos(β/2))/sin(β/2)想来你是只关心结果,而不必过程的,(过程其实不难。)