一个关于链表的问题！ 火急！！！

Question

PmyLik = ^myLink;
          myLink=Record
             linkname:String;
             nextLink:PmyLink;
          end;

Answer 1

type
    plink=^mylink
    mylink=record
       linkname:string;
       nextlink:plink;
    end;

Answer 2

TYPE 
          Link=^myLink;        
          myLink=Record
             linkname:String;
             nextLink:^Link;
          end;

Answer 3

TYPE 
          Link=^myLink;        
          myLink=Record
             linkname:String;
             nextLink:Link;
          end;
除了点小错！~——~

Answer 4

BlueTrees(蜗牛) ,robinhunter(深空) 都對
type
    plink=^mylink
    mylink=record
       linkname:string;
       nextlink:plink;
    end;

Answer 5

type
    plink=^mylink
    mylink=record
       linkname:string;
       nextlink:plink;
    end;