如
- <LineItem>
<LineItemNumber>000010</LineItemNumber>
<Material>839676</Material>
<MaterialDescription>MOTHER BD BOXD845BGL ATX PENTIUM (R) 4 }</MaterialDescription>
<CustomerPartNumber>12759</CustomerPartNumber>
<PlanShipDate>20020318</PlanShipDate>
<LineItemQuantity>225.000</LineItemQuantity>
+ <PickingRequest>
<BatchIdentifier>CN12113FOX</BatchIdentifier>
<Quantity>160.000</Quantity>
</PickingRequest>
+ <PickingRequest>
<BatchIdentifier>CN12114FOX</BatchIdentifier>
<Quantity>65.000</Quantity>
</PickingRequest>
</LineItem>下有兩個</PickingRequest> 節點﹐怎么獲得重復的個數
- <LineItem>
<LineItemNumber>000010</LineItemNumber>
<Material>839676</Material>
<MaterialDescription>MOTHER BD BOXD845BGL ATX PENTIUM (R) 4 }</MaterialDescription>
<CustomerPartNumber>12759</CustomerPartNumber>
<PlanShipDate>20020318</PlanShipDate>
<LineItemQuantity>225.000</LineItemQuantity>
+ <PickingRequest>
<BatchIdentifier>CN12113FOX</BatchIdentifier>
<Quantity>160.000</Quantity>
</PickingRequest>
+ <PickingRequest>
<BatchIdentifier>CN12114FOX</BatchIdentifier>
<Quantity>65.000</Quantity>
</PickingRequest>
</LineItem>下有兩個</PickingRequest> 節點﹐怎么獲得重復的個數
<LineItemNumber>000010</LineItemNumber>
<Material>839676</Material>
<MaterialDescription>MOTHER BD BOXD845BGL ATX PENTIUM (R) 4 }</MaterialDescription>
<CustomerPartNumber>12759</CustomerPartNumber>
<PlanShipDate>20020318</PlanShipDate>
<LineItemQuantity>225.000</LineItemQuantity>
+ <PickingRequest>
+ <PickingRequest>
</LineItem>
下有兩個<PickingRequest> 節點﹐怎么獲得這個重復節點的個數
在按扭事件中写代码:
var
i: integer;
ChildCount: integer;//子节点个数
xn: IXMLNode;//XML文档的树结点
begin
XMLDocument1.LoadFromFile('test.xml');
XMLDocument1.Active := True;
xn := XMLDocument1.DocumentElement.ChildNodes[0];//xn表示当前节点为根元素的第一个节点
xnOrder := xn.ChildNodes['items'];//items为xn的节点,节点名为items
ChildCount := xnOrder.ChildNodes.Count;//取items节点的子节点个数
if ChildCount > 0 then
begin
Application.MessageBox('有子节点','提示',MB_ICONINFORMATION + MB_OK);
end;
获取其它节点的子节点个数与此类似...
-----------------------------------------------------------
针对你的问题,如果<PickingRequest>是跟节点的第N个节点,那程序应该这样:
xn := XMLDocument1.DocumentElement.ChildNodes[N-1];
//也就是你上面的 第一个<PickingRequest>节点的子节点个数
ChildCount := xn.ChildNodes.Count;
同理,第二个<PickingRequest>节点的子节点个数应该是
xn := XMLDocument1.DocumentElement.ChildNodes[N];
ChildCount := xn.ChildNodes.Count;