if OpenDialog.Execute then
// OpenDialog.FileName:='C:\test.txt'; //默认赋予一文件路径
with OpenDialog.Files do
for I:=0 to Count-1 do
begin
AssignFile(F, Strings[I]);
Reset(F);
while not Eof(F) do
begin
Readln(F, FirstLine);
ListBox1.Items.Add(FirstLine);
end;
CloseFile(F);
end; if OpenDialog.Execute then 每次读取默认的文件.不希望人工去选择.请问该这么做?
// OpenDialog.FileName:='C:\test.txt'; //默认赋予一文件路径
with OpenDialog.Files do
for I:=0 to Count-1 do
begin
AssignFile(F, Strings[I]);
Reset(F);
while not Eof(F) do
begin
Readln(F, FirstLine);
ListBox1.Items.Add(FirstLine);
end;
CloseFile(F);
end; if OpenDialog.Execute then 每次读取默认的文件.不希望人工去选择.请问该这么做?
Const csFileName = 'C:\test.txt ';begin AssignFile(F, csFileName);
Reset(F);
while not Eof(F) do
begin
Readln(F, FirstLine);
ListBox1.Items.Add(FirstLine);
end;
CloseFile(F); end;
你上边的代码,OpenDialog.Files 是指在对话框中,可以选择多个文件,然后来个for循环处理,
如果这样的话,那就需要定义多个默认的字符串