如何把一个16进制字符转换为10进制?
(1)方法1
Function HexToDec(const Value :Integer ) : string;
var
s : string;
begin
s := '$' + IntToStr(Value);
Result := InToStr(StrToInt(s));
end;(2)方法2
Funtion HexToDec(const Value :Integer) : string;
CONST HEX : ARRAY['A'..'F'] OF INTEGER = (10,11,12,13,14,15);
VAR
str : String;
In : Integer;
i : integer;
BEGIN
Str := UpperCase(IntToStr(Value));
Int := 0;
FOR i := 1 TO Length(str) DO
IF str[i] < 'A' THEN
Int := Int * 16 + ORD(str[i]) - 48
ELSE
Int := Int * 16 + HEX[str[i]];
Result := IntToStr(Int);
end;
(1)方法1
Function HexToDec(const Value :Integer ) : string;
var
s : string;
begin
s := '$' + IntToStr(Value);
Result := InToStr(StrToInt(s));
end;(2)方法2
Funtion HexToDec(const Value :Integer) : string;
CONST HEX : ARRAY['A'..'F'] OF INTEGER = (10,11,12,13,14,15);
VAR
str : String;
In : Integer;
i : integer;
BEGIN
Str := UpperCase(IntToStr(Value));
Int := 0;
FOR i := 1 TO Length(str) DO
IF str[i] < 'A' THEN
Int := Int * 16 + ORD(str[i]) - 48
ELSE
Int := Int * 16 + HEX[str[i]];
Result := IntToStr(Int);
end;
function DecToBinStr(n: integer): string;
var
S: string;
i: integer;
Negative: boolean;
begin
if n < 0 then
Negative := true
else
Negative := False; n := Abs(n);
for i := 1 to SizeOf(n) * 8 do
begin
if n < 0 then
S := S + '1'
else
S := S + '0'; n := n shl 1;
end;
Delete(S,1,Pos('1',S) - 1);//remove leading zeros
if Negative then
S := '-' + S;
Result := S;
end;