struts项目，tomcat报错，帮帮我好吗？

Question

parameter="Logon"  提交時這個參數有沒有值
logon.do?Logon=submit

Answer 1

GuoYangHai:
我的LongonAction.java里有这个参数：
public class LogonAction extends Action 
{ 
   public ActionForward executeAction(ActionMapping mapping,ActionForm form,HttpServletRequest request,HttpServletResponse response)throws ServletException
   { 
    ActionForward myforward = null;
        if (isCancelled(request))
{
 return mapping.findForward("cancel");
} String myaction = mapping.getParameter();
    if ("Logon".equalsIgnoreCase(myaction)) {
 myforward = performLogon(mapping, form, request, response);
}
else
    {
      throw new ServletException("Parameter Error");
     }      return myforward;
  }
        
 private ActionForward performLogon(ActionMapping mapping,ActionForm actionForm,HttpServletRequest request,HttpServletResponse response)throws ServletException
 {
  
  LogonForm theForm = (LogonForm)actionForm; 
    String user = theForm.getUsername(); 
    String password = theForm.getPassword(); 
    request.setAttribute("user", user); 
    request.setAttribute("password", password); 
        return mapping.findForward("sucess"); 
 }
}

Answer 2

sadenXu:
怎么配置servlet呢，是不是在web.xml里：
 <servlet>
    <servlet-name>action</servlet-name>
    <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
    <init-param>
      <param-name>config</param-name>
      <param-value>/WEB-INF/struts-config.xml</param-value>
    </init-param>
    <init-param>
      <param-name>debug</param-name>
      <param-value>2</param-value>
    </init-param>
    <init-param>
      <param-name>detail</param-name>
      <param-value>2</param-value>
    </init-param>
    <load-on-startup>2</load-on-startup>
  </servlet>

Answer 3

do you have the following?!-- Standard Action Servlet Mapping  -->
  <servlet-mapping>
    <servlet-name>action</servlet-name>
    <url-pattern>*.do</url-pattern>
  </servlet-mapping>

Answer 4

你的action是LogonForm，怎么在form里又用logon.do