哪位大侠用jsp+xml做过后台管理程序 不使用数据库 ？急啊 !```

Question

做过。但是数据太多了不行，少还可以。
数据多就把一个大xml切成多个小xml

Answer 1

<?xml version="1.0" encoding="UTF-8"?><database>
<ServerName>myLocalHost</ServerName>
<DatabaseName>myDatabaseName</DatabaseName>
</database>
package com.myproject.test;import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;import org.w3c.dom.Document;
import org.w3c.dom.NodeList;public class ReadDatabase {
public static String serverName; public static String databaseName; public static String userName; public static String password; public static void readDatabase1() { DocumentBuilderFactory theDocumentBuilderFactory = DocumentBuilderFactory
.newInstance();
String path = "D:\\Projects\\myproject\\src\\com\\myproject\\test\\database.xml";
try {
DocumentBuilder theDocumentBuilder = theDocumentBuilderFactory
.newDocumentBuilder();
Document theDocument = theDocumentBuilder.parse(path);
theDocument.getDocumentElement(); NodeList nodelist; nodelist = theDocument.getElementsByTagName("ServerName");
if (nodelist.getLength() > 0) {
serverName = (nodelist.item(0)).getFirstChild().getNodeValue();
System.out.println(nodelist.item(0).getNodeName() + "="
+ serverName);
} nodelist = theDocument.getElementsByTagName("DatabaseName");
if (nodelist.getLength() > 0) {
databaseName = (nodelist.item(0)).getFirstChild()
.getNodeValue();
System.out.println(nodelist.item(0).getNodeName() + "="
+ databaseName);
} nodelist = theDocument.getElementsByTagName("UserName");
if (nodelist.getLength() > 0) {
userName = (nodelist.item(0)).getFirstChild().getNodeValue();
System.out.println(nodelist.item(0).getNodeName() + "="
+ userName);
} nodelist = theDocument.getElementsByTagName("Password");
if (nodelist.getLength() > 0) {
password = (nodelist.item(0)).getFirstChild().getNodeValue();
System.out.println(nodelist.item(0).getNodeName() + "="
+ password);
} } catch (Exception e) {
e.printStackTrace();
} } public static void main(String args[]) {
readDatabase1();
}}

Answer 2

我所说的不是这个　是一个完整的程序可是对xml进行增删改查，最好还支持模糊查询