怎样把一个字符串转换成一个长整形数组？

Question

例如： "1112,1245,1457,1123,"

Answer 1

str="1112,1245,1457,1123,";
String[] strarr = str.spit(",");
for(int i=0;i<strarr.lengt....){
   strarr[i] ...
}

Answer 2

import java.util.*;
public class TestString{
public static void main(String[] args){
String s= "1112,1245,1457,1123,";
String[] st =s.split(",");
long[] l= new long[st.length];
for(int i=0;i<st.length;i++){
l[i] =Long.parseLong(st[i]);
}
System.out.println(Arrays.toString(l));
}
}

Answer 3

str="1112,1245,1457,1123,";
StringTokenizer st= new  StringTokenizer(str,",");
        String[] sCodes = new String[st.countTokens()];
        int i=0;
        if(st!=null&&st.countTokens()>0){
            while(st.hasMoreElements()){
                sCodes[i]=(String)st.nextElement();
i++;
            }
}

Answer 4

StringTokenizer st = new StringTokenizer("1112,1245,1457,1123",",");
long lst[];
int i=0;
     while (st.hasMoreTokens()) {
        lst[i]=st.nextToken();
     }