private String queryOrgDn(String parentid,String dn){
System.out.println("parentid : " +parentid);
int len = parentid.trim().length();
while(len > 5) {
AndFilter filter = new AndFilter();
filter.and(new EqualsFilter("objectclass","uumOrg"));
filter.and(new EqualsFilter("ESSPorgId",parentid));
List<Org> alist = ldapTemplate_user.search("", filter.encode(),new OrgAttributeMapper());
System.out.println("alist : " + alist.size());
if(null!=alist&&0<alist.size()){
Org _aorg = alist.get(0);
String _parentid = _aorg.getESSPparentId();
String _dn = dn + _aorg.getOu();
queryOrgDn(_parentid,_dn);//@2 这里循环调用此方法
}else break;
}
return dn;//@1
}我打断点调试过了,在运行到@1处后,程序又会回到@2处,陷入死循环。不是很懂递归调用,请指教!谢谢递归Java
if(某个条件) return 确定的值
else return function(XXX的某个表达式)
}
System.out.println("parentid : " +parentid);
int len = parentid.trim().length();
while(len > 5) {
AndFilter filter = new AndFilter();
filter.and(new EqualsFilter("objectclass","uumOrg"));
filter.and(new EqualsFilter("ESSPorgId",parentid));
List<Org> alist = ldapTemplate_user.search("", filter.encode(),new OrgAttributeMapper());
System.out.println("alist : " + alist.size());
if(null!=alist&&0<alist.size()){
Org _aorg = alist.get(0);
String _parentid = _aorg.getESSPparentId();
String _dn = dn + _aorg.getOu();
return queryOrgDn(_parentid,_dn);//此处加了一个return
}else break;
}
return dn;
}
System.out.println("parentid : " +parentid);
int len = parentid.trim().length();
while(len > 5) {
AndFilter filter = new AndFilter();
filter.and(new EqualsFilter("objectclass","uumOrg"));
filter.and(new EqualsFilter("ESSPorgId",parentid));
List<Org> alist = ldapTemplate_user.search("", filter.encode(),new OrgAttributeMapper());
System.out.println("alist : " + alist.size());
if(null!=alist&&0<alist.size()){
Org _aorg = alist.get(0);
String _parentid = _aorg.getESSPparentId();
String _dn = dn + _aorg.getOu();
return queryOrgDn(_parentid,_dn);//此处加了一个return
}else break;
}
return dn;
}
递归是自己调用自己,你不return的话,上一层调用就得不到返回值