另求一正则表达式！ >..<

String strs="[010001][2] "
 +"[100001][1] "
 +"出口温度[320001] "
 +"出口压力[540002] "
 +"√ ;怎样用正则表达示得到标签类似[100001][1],出口温度[320001]里面所有的内容？用集合存起来。

解决方案 »

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have a try
String reg = "(?:<SPAN|<span)\\s*.*?>\\s*(.*?)?\\s*(?:|)";
Pattern p = Pattern.compile(reg);
Matcher m = p.matcher(strs);
List<String> list = new ArrayList<String>();
while (m.find()) {
 list.add(m.group(1));
 System.out.println(m.group(1));
}
public static void main(String[] args) {
String strs="[010001][2] "
 +"[100001][1] "
 +"出口温度[320001] "
 +"出口压力[540002] "
 +"√ ";
List<String> list = new ArrayList<String>();
Matcher m = Pattern.compile("(?is)<span.*?>(.*?)").matcher(strs);
while(m.find()){
//System.out.println(m.group(1));
list.add(m.group(1));
}
System.out.println(list);
}
这个好像可以。String regex = "<SPAN[^>]*>([^<]*|[^<]*)";
Pattern p = Pattern.compile(regex);
        Matcher m = p.matcher(strs);
        while(m.find())
        {
            System.out.println(m.group(1));
        }
用is标志好一点
LS的怎么都不考虑一下标签分开空格，比如一个标签
<SPANA xxx>yyyy，一个非法的标签也被扫面通过了String reg = "(?is:<span)\\s*.*?>\\s*(.*?)?\\s*(?is:)";
Pattern p = Pattern.compile(reg);
Matcher m = p.matcher(strs);
List<String> list = new ArrayList<String>();
while (m.find()) {
 list.add(m.group(1));
 System.out.println(m.group(1));
}
String reg = "(?is:<span)\\s+.*?>\\s*(.*?)?\\s*(?is:)";
String strs="[010001][2] "
 +"[100001][1] "
 +"出口温度[320001] "
 +"出口压力[540002] "
 +"√ "
 +"<SPANXX id=xxx>yyy"; //for example
Pattern p = Pattern.compile(reg);
Matcher m = p.matcher(strs);
List<String> list = new ArrayList<String>();
while (m.find()) {
 list.add(m.group(1));
 System.out.println(m.group(1));
}
可能是我阐述问题有错误，大家都没明白我意思>..<
我要的集合是存放类似[100001][1],XXXXXX[320001]的内容，而不要最后一个 √ 
(XXXXXX---代表任意文字)
String reg = "(?is:<span)\\s+.*?>\\s*((?!<.*?>\\s*)(.*?)(?!</.*?>))\\s*(?is:)";
String strs="[010001][2] "
 +"[100001][1] "
 +"出口温度[320001] "
 +"出口压力[540002] "
 +"<a>√ </a>"
 +"<SPANXX id=xxx>yyy"; //for example
Pattern p = Pattern.compile(reg);
Matcher m = p.matcher(strs);
List<String> list = new ArrayList<String>();
while (m.find()) {
 list.add(m.group(2));
 System.out.println(m.group(2));
}
maybe this is better
String reg = "(?is:<span)\\s+.*?>\\s*((?:<.*?>\\s*)*(.*?)(?:</.*?>)*)\\s*(?is:)";
String strs="[010001][2] "
 +"[100001][1] "
 +"出口温度[320001] "
 +"<a>出口?力[540002] </a>"
 +"<a>√ </a>"
 +"<SPANXX id=xxx>yyy"; //for example
Pattern p = Pattern.compile(reg);
Matcher m = p.matcher(strs);
List<String> list = new ArrayList<String>();
while (m.find()) {
 list.add(m.group(2));
 System.out.println(m.group(2));
}
ArrayList<String> al = new ArrayList<String>();
Pattern p = Pattern.compile("(<SPAN.*?>)([^\\d]*?(?:\\d+?)[^\\d[^<]]*?)(?=[<])");
String str = "[010001][2] "
 +"[100001][1] "
 +"出口温度[320001] "
 +"出口压力[540002] "
 +"√ ";
Matcher m = p.matcher(str);
while(m.find()) {
al.add(m.group(2));
System.out.println(m.group(2));
}