各位再帮帮忙分析JTable代码

Question

setSelectedRow
setSelectedColumn
(JTable的方法)

Answer 1

singer1976(晃晃悠悠) ,你真是"晃晃悠悠)"

Answer 2

import javax.swing.*;
import javax.swing.table.*;
import java.awt.*;
public class no2 extends JApplet{
  ......
  JTable jt=new JTable();
jt.addKeyListener(new java.awt.event.KeyListener() { 
 public void keyPressed(KeyEvent e) {
   int selected;JDialog jfr=new JDialog();
 selected = jt.getSelectedRow();
    int col=jt.getSelectedColumn();
    int cct=jt.getColumnCount();
    int keycode=e.getKeyCode();
    //if( selected>=0 && col>=0 && col+1<cct){
    if(keycode==KeyEvent.VK_ENTER && col+1<=cct && col==0){
    //System.out.println(selected);
    //System.out.println(jt.getValueAt(selected,col));
    String calls=jt.getValueAt(selected,col).toString();
JLabel tmpj=new JLabel("该表格共"+cct+"列。"+"您在第"+(selected+1)+"行第"+(col+1)+"单元格处输入了字符："+calls,JLabel.CENTER);
  jfr.getContentPane().add(tmpj);jfr.setSize(600,400);jfr.show();//问问问：：：为什么在这里加上弹出窗口后，就不能TAB到下一个单元格中去？？？？？？？？？？？？？？
jt.setColumnSelectionInterval(col+1,selected);
                             }              }
public void keyTyped(KeyEvent e){}
public void keyReleased(KeyEvent e){}
                                                   });
......                   }
}