一个菜鸟的关于InetAddress的问题

Question

        InetAddress local = InetAddress.getByName(null);        InetAddress a = InetAddress.getByName(args[0]);

Answer 1

InetAddress localip=InetAddress.getLocalHost();
String localIp=ip.getHostAddress();             //获得本地主机ip.
String localName=ip.getHostName();           //获得本地主机名称

Answer 2

检查一下InetAddress.getByName(...)中的参数是字符串吗？

Answer 3

package net;import java.awt.*;
import java.applet.*;
import java.io.*;
import java.net.*;
import java.util.*;
public class Net2 extends Applet {
    Panel panel1,panel2;
    TextField text1=new TextField(10);
    TextField text2=new TextField();
    TextArea  area=new TextArea(7,10);
    Label label=new Label("请输入对方IP");
    Button ok=new Button("确定");
    Button button=new Button("发送");
    InetAddress address;
    
    DatagramSocket socket;
    byte[] obuf=new byte[10240];
    byte[] ibuf=new byte[10240];
    DatagramPacket out;
    DatagramPacket in=new DatagramPacket(ibuf,ibuf.length);
public void init() {
         .....
                  .....
                  
                 show();
   } public boolean action(Event evt,Object args){
    if((evt.target==button)){
     area.append('\n'+"我说："+text2.getText());
     text2.setText("");     }
if ((evt.target==ok)||(text1.getText()!=null)){
                 address=InetAddress.getByName(text1.get()):
                 ......
                 ......
}
return true;}}问题就在最后那里

Answer 4

>> address=InetAddress.getByName(text1.get()):
                                 ^^^^^^^^^^^ 
                                 有这个方法吗？ text1.getText()吧？

Answer 5

不明白,我的也是那样的,没有错误阿
address=InetAddress.getByName(text1.get()):
最后改成分号,你的是冒号