请大家写出满足如下要求的正则表达式

Question

使用正则表达式，以实现下面的功能： 
1）不可以为空 
2）允许含有特殊字符：! $ % & \ () - / ; < ? [] ^ {} 
3）必须同时含有半角英文大写字母、半角英文小写字母以及半角数字 
4）8文字以上，16文字以下 

Answer 1

此回复为自动发出,仅用于显示而已，并无任何其他特殊作用
楼主【tteesstt】截止到2008-07-15 22:23:53的历史汇总数据(不包括此帖)：
发帖的总数量:109                      发帖的总分数:7000                     每贴平均分数:64                       
回帖的总数量:76                       得分贴总数量:8                        回帖的得分率:10%                      
结贴的总数量:108                      结贴的总分数:6900                     
无满意结贴数:0                        无满意结贴分:0                        
未结的帖子数:1                        未结的总分数:100                      
结贴的百分比:99.08 %               结分的百分比:98.57 %                  
无满意结贴率:0.00  %               无满意结分率:0.00  %                  
值得尊敬

Answer 2

这样行不行？？ public static void main(String[] args) {
System.out.println(regexText(""));
System.out.println(regexText("123"));
System.out.println(regexText("A4783"));
System.out.println(regexText("zA25$4783"));
System.out.println(regexText("z457E{"));
System.out.println(regexText("524754x1&#"));
System.out.println(regexText("10248Zgk@"));
System.out.println(regexText("102xfas44dsfdhd48Zgk@"));
}

public static boolean regexText(String value) {
return value.matches("^(?=.*\\p{Punct})(?=.*\\p{Alnum}).{8,16}$");
}

Answer 3

关于长度的测试不会写，只好用2个正则，一个判断数据，另一个判断长度public class T {
  public static void main(String[] args) {
    System.out.println(regexText("13a4C5fdsfiaf"));
    System.out.println(regexText("123"));
    System.out.println(regexText("A47c83"));
    System.out.println(regexText("ZA25$4783"));
    System.out.println(regexText("z457E{"));
    System.out.println(regexText("524754x1&#"));
    System.out.println(regexText("10248Zgk@"));
    System.out.println(regexText("102xfas44dsfdhd48Zgk@"));
  }  public static boolean regexText(String value) {
    String all = "[\\p{Graph}]{0,}";
    StringBuilder b = new StringBuilder();
    b.append("(" + all + "[0-9]+" + all + "[a-z]+" + all + "[A-Z]+" + all + ")");
    b.append("|");
    b.append("(" + all + "[0-9]+" + all + "[A-Z]+" + all + "[a-z]+" + all + ")");
    b.append("|");
    b.append("(" + all + "[a-z]+" + all + "[0-9]+" + all + "[A-Z]+" + all + ")");
    b.append("|");
    b.append("(" + all + "[a-z]+" + all + "[A-Z]+" + all + "[0-9]+" + all + ")");
    b.append("|");
    b.append("(" + all + "[A-Z]+" + all + "[a-z]+" + all + "[0-9]+" + all + ")");
    b.append("|");
    b.append("(" + all + "[A-Z]+" + all + "[0-9]+" + all + "[a-z]+" + all + ")");
    return value.matches(b.toString()) && value.matches("[\\p{Graph}]{8,16}");
  }
}运行结果为
true
false
false
false
false
false
true
false

Answer 4

value.matches("^(?=.*\\p{Punct})(?=.*\\p{Alnum}).{8,16}$");

Answer 5

不好意思,忽略了"同时"了. 下面这样行不行?    public static void main(String[] args) {
        System.out.println(regexText(""));
        System.out.println(regexText("123"));
        System.out.println(regexText("A4783"));
        System.out.println(regexText("zA25$4783"));
        System.out.println(regexText("z457E{"));
        System.out.println(regexText("524754x1&#"));
        System.out.println(regexText("10248Zgk@"));
        System.out.println(regexText("102xfas44dsfdhd48Zgk@"));
        System.out.println(regexText("xfAs.!.dsf5dhdoo"));
    }
    
    public static boolean regexText(String value) {
        return value.matches("^(?=.*\\p{Punct})(?=.*\\p{Lower})(?=.*\\p{Upper})(?=.*\\p{Digit}).{8,16}$");
    }

Answer 6

晕,又看错了...2）允许含有特殊字符：! $ % & \ () - / ; < ? [] ^ {} 看成必须了..

Answer 7

"^(?=.*\\p{Punct})(?=.*\\p{Lower})(?=.*\\p{Upper})(?=.*\\p{Digit}).{8,16}$"

Answer 8

public class T {
  public static void main(String[] args) {
    System.out.println(regexText("13a4C5fdsfiaf"));
    System.out.println(regexText("123"));
    System.out.println(regexText("A47c83"));
    System.out.println(regexText("ZA25$4783"));
    System.out.println(regexText("z457E{"));
    System.out.println(regexText("524754x1&#"));
    System.out.println(regexText("10248Zgk@"));
    System.out.println(regexText("102xfas44dsfdhd48Zgk@"));
  }  public static boolean regexText(String value) {
    String all = "[\\p{Graph}]{0,}";
    StringBuilder b = new StringBuilder();
    b.append("(" + all + "[0-9]+" + all + "[a-z]+" + all + "[A-Z]+" + all + ")");
    b.append("|");
    b.append("(" + all + "[0-9]+" + all + "[A-Z]+" + all + "[a-z]+" + all + ")");
    b.append("|");
    b.append("(" + all + "[a-z]+" + all + "[0-9]+" + all + "[A-Z]+" + all + ")");
    b.append("|");
    b.append("(" + all + "[a-z]+" + all + "[A-Z]+" + all + "[0-9]+" + all + ")");
    b.append("|");
    b.append("(" + all + "[A-Z]+" + all + "[a-z]+" + all + "[0-9]+" + all + ")");
    b.append("|");
    b.append("(" + all + "[A-Z]+" + all + "[0-9]+" + all + "[a-z]+" + all + ")");
    return value.matches(b.toString()) && value.matches("[\\p{Graph}]{8,16}");
  }
}：! $ % & \ () - / ; < ? [] ^ {} 

Answer 9

这下应该没问题了.    public static void main(String[] args) {
        System.out.println(regexText(""));
        System.out.println(regexText("123"));
        System.out.println(regexText("A4783"));
        System.out.println(regexText("zA25$4783"));
        System.out.println(regexText("z4uu3j57E{"));
        System.out.println(regexText("524754x1&#"));
        System.out.println(regexText("10248Zgk@"));
        System.out.println(regexText("102xfas44dsfdhd48Zgk@"));
        System.out.println(regexText("xfAs!dsf5dh&doo"));
        System.out.println(regexText("xfAsmdsf5dhdoo"));    }
    
    public static boolean regexText(String value) {
        return value.matches("^(?=.*\\p{Lower})(?=.*\\p{Upper})(?=.*\\p{Digit})(.((?<!\\p{Punct})|(?<=[-!$%&()/;<?{}\\[\\]\\\\^]))){8,16}$");
    }

Answer 10

false
false
false
true
true
false
false
false
true
true

Answer 11

import java.util.regex.Pattern;public class Test01 {    public static void main(String[] args) {
        String[] strs = {
                "",
                "123",
                "A4783",
                "zA25$4783",
                "z4uu3j57E{",
                "524754x1&#",
                "10248Zgk@",
                "102xfas44dsfdhd48Zgk@",
                "xfAs!dsf5dh&doo",
                "xfAsmdsf5dhdoo"
            };        // 限定条件
         final String CONDITION = "(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)";        // 允许出现的字符
         final String SPECIAL_CHAR = "[-A-Za-z0-9!$%&()/;<?{}\\[\\]^\\\\]";        // 数量
         final String QUANTITY = "{8,16}";        Pattern pattern = Pattern.compile(CONDITION + SPECIAL_CHAR + QUANTITY);        for(String str : strs) {
            System.out.println(pattern.matcher(str).matches());
        }
    }
}

Answer 12

请 火龙果 到 http://topic.csdn.net/u/20080716/22/80cdd418-a0e9-4e7e-8435-df6d4bc11c4a.html给解释一下您的正则好吗？拜托了！！！