求一个工具类，能把'一'，‘二’，‘二十一’等中文数字转换为阿拉伯数字1，2，21等

写个方法做好character之间的映射
如'一'映射'1'
...

public class Change {
    char[] num = new char[]{'一','二','三','四','五','六','七','八','九'};
    char[] sign = new char[]{'十','百','千','万','亿'};
    public Change() {
System.out.println(change("五万"));
    }
    private  long change(String old){
long num = 0;
old = old.replaceAll("零","");
old = old.replaceAll("百十","百一十");
old = old.replaceAll("千十","千一十");
old = old.replaceAll("万十","万一十");
old = old.replaceAll("亿十","亿一十");
if(old.charAt(0)=='十')
    old = "一"+old; for(int i = 0 ; i < old.length();i++){
    if(isNum(old.charAt(i)))
num += getRate(old.charAt(i))*getSign(i+1,old);
}
return num;
    }

    private boolean isNum(char c){
for(int i = 0;i <num.length;i++){
    if(num[i] == c)
return true;
}
return false;
    }

    private long getSign(int start,String s){
long sign = 1;
long max = 1;
for(int i = start;i<s.length();i++){
    char c = s.charAt(i);
    long r = getRate(c);
    if(r>max)
max *= r;
    else
max = 1;
    if(max>sign)
sign *= max;
}
return sign;
    }

    private long getRate(char c){
long rate = 0;
switch(c){
    case '一':rate = 1;break;
    case '二':rate = 2;break;
    case '三':rate = 3;break;
    case '四':rate = 4;break;
    case '五':rate = 5;break;
    case '六':rate = 6;break;
    case '七':rate = 7;break;
    case '八':rate = 8;break;
    case '九':rate = 9;break;
    case '十':rate = 10;break;
    case '百':rate = 100;break;
    case '千':rate = 1000;break;
    case '万':rate = 10000;break;
    case '亿':rate = 100000000;break;
    default:rate=0;break;
}
return rate;
    }

    public static void main(String arg[]){
new Change();
    }

}估计会有BUG。不过我试的数都行。

顶楼上的。。有BUG，不过看着应该没什么问题吧。

getSign()方法有问题。
十亿输出一百亿，
百亿输出一千亿。

修改了一下public class Change {
    char[] num = new char[]{'一','二','三','四','五','六','七','八','九'};
    char[] sign = new char[]{'十','百','千','万','亿'};
    public Change() {
    System.out.println(change("十亿九千四百二十"));
    }
    private  long change(String old){
    long num = 0;
    old = old.replaceAll("零","");
    old = old.replaceAll("百十","百一十");
    old = old.replaceAll("千十","千一十");
    old = old.replaceAll("万十","万一十");
    old = old.replaceAll("亿十","亿一十");
    if(old.charAt(0)=='十')
      old = "一"+old;
    for(int i = 0 ; i < old.length();i++){
        if(isNum(old.charAt(i)))
        num += getRate(old.charAt(i))*getSign(i+1,old);
    }
    return num;
    }

    private boolean isNum(char c){
    for(int i = 0;i <num.length;i++){
        if(num[i] == c)
        {
         return true;
        }
    }
    return false;
    }

    private long getSign(int start,String s){
    long sign = 1;
    long max = 1;
    for(int i = start;i<s.length();i++){
        char c = s.charAt(i);
        long r = getRate(c);
        if(r>max)
        max *= r;
        else
        max = 1;
        if(max>sign)
        sign *= max;
    }
    if(sign>10000)
     return sign/10;
    return sign;
    }

    private long getRate(char c){
    long rate = 0;
    switch(c){
        case '一':rate = 1;break;
        case '二':rate = 2;break;
        case '三':rate = 3;break;
        case '四':rate = 4;break;
        case '五':rate = 5;break;
        case '六':rate = 6;break;
        case '七':rate = 7;break;
        case '八':rate = 8;break;
        case '九':rate = 9;break;
        case '十':rate = 10;break;
        case '百':rate = 100;break;
        case '千':rate = 1000;break;
        case '万':rate = 10000;break;
        case '亿':rate = 100000000;break;
        default:rate=0;break;
    }
    return rate;
    }

    public static void main(String arg[]){
    new Change();
    }

}

我上边发的还有点BUG
show againpublic class Change {
    char[] num = new char[]{'一','二','三','四','五','六','七','八','九'};
    char[] sign = new char[]{'十','百','千','万','亿'};
    public Change() {
    System.out.println(change("九亿九万四百二十"));
    }
    private  long change(String old){
    long num = 0;
    old = old.replaceAll("零","");
    old = old.replaceAll("百十","百一十");
    old = old.replaceAll("千十","千一十");
    old = old.replaceAll("万十","万一十");
    old = old.replaceAll("亿十","亿一十");
    if(old.charAt(0)=='十')
      old = "一"+old;
    for(int i = 0 ; i < old.length();i++){
        if(isNum(old.charAt(i)))
        num += getRate(old.charAt(i))*getSign(i+1,old);
    }
    return num;
    }

    private boolean isNum(char c){
    for(int i = 0;i <num.length;i++){
        if(num[i] == c)
        {
         return true;
        }
    }
    return false;
    }

    private long getSign(int start,String s){
    long sign = 1;
    long max = 1;
    for(int i = start;i<s.length();i++){
        char c = s.charAt(i);
        long r = getRate(c);
        if(r>max)
        max *= r;
        else
        max = 1;
        if(max>sign)
        sign *= max;
    }
    if(s.charAt(0)=='十'&&sign>10000)
     return sign/10;
    return sign;
    }

    private long getRate(char c){
    long rate = 0;
    switch(c){
        case '一':rate = 1;break;
        case '二':rate = 2;break;
        case '三':rate = 3;break;
        case '四':rate = 4;break;
        case '五':rate = 5;break;
        case '六':rate = 6;break;
        case '七':rate = 7;break;
        case '八':rate = 8;break;
        case '九':rate = 9;break;
        case '十':rate = 10;break;
        case '百':rate = 100;break;
        case '千':rate = 1000;break;
        case '万':rate = 10000;break;
        case '亿':rate = 100000000;break;
        default:rate=0;break;
    }
    return rate;
    }

    public static void main(String arg[]){
    new Change();
    }

}

/**
* 中文数字其实很有规律, 一个数字, 然后跟着一个表示级别的标志,如千,百,十,万.
* 这个级别表达得不好, 但是不知道怎么表达, 知道意思就行
*
* 所以读取的时候, 读一个数字, 再读一个表示级别的标志, 计算一次
* 直到数字读完.
*
* 没有处理那个变态的五万万这种情况, 其实也不难, 在处理数字的循环中加个判断
* 这就得预先读取下一个符, 直到是数字为止, 判断其间有多少个级别标志
*/
public class Test {
    // 建立数组, 用来查找各级的标志, 这一级的值为Math.pow(10, 下标 + 1);
    public static char[] spliter = { '十', '百', '千', '万' };
    // 建立数组, 用来查找中文中的数字与何拉伯数字的对应关系,
    // 下标值为相应阿拉伯数字的值
    public static char[] number  = { '零', '一', '二', '三', '四', '五', '六', '七',
            '八', '九'            };    // 存放中文的数值
    private String       data    = "三千四百五十一";    public Test(String data) {
        this.data = data;
    }    /**
     * 返回中文数字的阿拉伯数字的值.
     */
    public int parse() {
        int result = 0;        int index = 1; // 如果第一个字符是级别标志, 这时就用到了index=1这个值
        for (int i = 0; i < data.length(); ++i) {
            index = 1;

            if (isNumber(data.charAt(i))) {
                // 是数字, 则找到在建立的中文数字的数组中的下标,
                // 即为他的数值
                index = find(number, data.charAt(i));
            } else {
                // 读到一个级别标志时, 进行计算一次
                int temp = find(spliter, data.charAt(i));
                result = result + index * (int) Math.pow(10, temp + 1);
            }
        }        // 处理最后一个字符, 如果最后一个字符是数字, 则把加上他的值
        // 因为前面是读取级别标志时才进行计算一次.
        int last = data.length() - 1;
        if (isNumber(data.charAt(last))) {
            result += find(number, data.charAt(last));
        }        return result;
    }    // 查找一个字符在给定数组中的位置
    public static int find(char[] array, char ch) {
        for (int i = 0; i < array.length; ++i) {
            if (array[i] == ch) {
                return i;
            }
        }        return -1;
    }    // 字符是否数字
    public static boolean isNumber(char ch) {
        for (int i = 0; i < Test.number.length; ++i) {
            if (ch == Test.number[i]) {
                return true;
            }
        }        return false;
    }    // 字符是否级别的标志
    public static boolean isSpliter(char ch) {
        for (int i = 0; i < Test.spliter.length; ++i) {
            if (ch == Test.spliter[i]) {
                return true;
            }
        }        return false;
    }    public static void main(String[] args) {
        Test test = new Test("九万四千四百一十八");
        //Test test = new Test("十八");
        //Test test = new Test("八");
        System.out.println(test.parse());
    }
}

package 把人民币转化为大写汉字;public class number {

    // 建立数组, 用来查找各级的标志, 这一级的值为Math.pow(10, 下标 + 1);
    public static char[] spliter = { '十', '百', '千', '万' };
    // 建立数组, 用来查找中文中的数字与何拉伯数字的对应关系,
    // 下标值为相应阿拉伯数字的值
    public static char[] number  = { '零', '一', '二', '三', '四', '五', '六', '七',
            '八', '九'};    // 存放中文的数值
    private String       data =null;    public number(String data) {
        this.data = data;
    }    /**
     * 返回中文数字的阿拉伯数字的值.
     */
    public int parse() {
        int result = 0;        int index = 1; // 如果第一个字符是级别标志, 这时就用到了index=1这个值
        for (int i = 0; i < data.length(); ++i) {

            if (isNumber(data.charAt(i))) {
                // 是数字, 则找到在建立的中文数字的数组中的下标,
                // 即为他的数值
                index = find(number, data.charAt(i));

            } else {
                // 读到一个级别标志时, 进行计算一次
                int temp = find(spliter, data.charAt(i));
                result = result + index * (int) Math.pow(10, temp + 1);            }
        }
        // 处理最后一个字符, 如果最后一个字符是数字, 则把加上他的值
        // 因为前面是读取级别标志时才进行计算一次.
        int last = data.length() - 1;
        if (isNumber(data.charAt(last))) {
            result += find(number, data.charAt(last));
        }        return result;
    }    // 查找一个字符在给定数组中的位置
    public static int find(char[] array, char ch) {
        for (int i = 0; i < array.length; ++i) {
            if (array[i] == ch) {
                return i;
            }
        }        return -1;
    }    // 字符是否数字
    public static boolean isNumber(char ch) {
        for (int i = 0; i < number.length; ++i) {
            if (ch == number[i]) {
                return true;
            }
        }        return false;
    }    // 字符是否级别的标志
    public static boolean isSpliter(char ch) {
        for (int i = 0; i < spliter.length; ++i) {
            if (ch == spliter[i]) {
                return true;
            }
        }        return false;
    }    public static void main(String[] args) {
        number test = new number("九万四千四百一十八");
        //Test test = new Test("十八");
        //Test test = new Test("八");
        System.out.println(test.parse());
    }
}

我也写一个,范围:0-99999999,没有做异常处理.public class CSDN
{    public static String[] f = { "十", "百", "千", "万" };    public static int length = f.length - 1;    public String getNum(String str)
    {
        int num = change(str, length);
        if (num <0)
        {
            return "error";
        }
        return num + "";
    }    public int change(String str, int l)
    {
        int total = 0;
        if (l < 0)
        {
            total += wordToNum(str);
        }
        else
        {
            String arr1[] = str.split(f[l]);            if (arr1.length > 2 && (l == 3))
            {
                return -1;
            }
            else if (arr1.length >= 2)
            {
                total += level(change(arr1[0], l), l);
                total += change(arr1[1], l);
            }
            else if (arr1.length == 1)
            {
                total += change(str, l - 1);
            }
        }
        return total;
    }    public int level(int str, int i)
    {
        int num = (int) ((Math.pow(10, i + 1)) * str);
        return num;
    }    public int wordToNum(String word)
    {
        int num = 0;
        String arr[] = { "零", "一", "二", "三", "四", "五", "六", "七", "八", "九", "十" };        for (int j = 0; j < length; j++)
        {
            if (word.endsWith(f[j]))
            {
                num = level(wordToNum(word.split(f[j])[0]), j);
                break;
            }
        }
        for (int i = 0, size = arr.length; i < size; i++)
        {
            if (word.equals(arr[i]) || word.equals("零" + arr[i]))
            {
                num = i;            }
        }
        return num;
    }    public static void main(String[] args)
    {
        String str = "六千零五十四万八千零九十";
        CSDN cal = new CSDN();        System.out.println(cal.getNum(str));
    }}

o,我看过了，
把
if(max>sign)
sign *= max;
改成
if(max>sign)
sign *= r;
就OK了。

我在java_net 2000的一个网页见过,数字和中文大写的互转程序,我去找找啊.
import java.math.BigDecimal; public class ConvertNumber {
  /** 定义数组存放数字对应的大写 */
  private final static String[] STR_NUMBER = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖" };   /** 定义数组存放位数的大写 */
  private final static String[] STR_MODIFY = { "", "拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟" };   /**
   * 转化整数部分
   *
   * @param tempString
   * @return 返回整数部分
   */
  private static String getInteger(String tempString) {
    /** 用来保存整数部分数字串 */
    String strInteger = null;//
    /** 记录"."所在位置 */
    int intDotPos = tempString.indexOf(".");
    int intSignPos = tempString.indexOf("-");
    if (intDotPos == -1)
      intDotPos = tempString.length();
    /** 取出整数部分 */
    strInteger = tempString.substring(intSignPos + 1, intDotPos);
    strInteger = new StringBuffer(strInteger).reverse().toString();
    StringBuffer sbResult = new StringBuffer();
    for (int i = 0; i < strInteger.length(); i++) {
      sbResult.append(STR_MODIFY[i]);
      sbResult.append(STR_NUMBER[strInteger.charAt(i) - 48]);
    }

    sbResult = sbResult.reverse();
    replace(sbResult, "零拾", "零");
    replace(sbResult, "零佰", "零");
    replace(sbResult, "零仟", "零");
    replace(sbResult, "零万", "万");
    replace(sbResult, "零亿", "亿");
    replace(sbResult, "零零", "零");
    replace(sbResult, "零零零", "零");
    /** 这两句不能颠倒顺序 */
    replace(sbResult, "零零零零万", "");
    replace(sbResult, "零零零零", "");
    /** 这样读起来更习惯. */
    replace(sbResult, "壹拾亿", "拾亿");
    replace(sbResult, "壹拾万", "拾万");
    /** 删除个位上的零 */
    if (sbResult.charAt(sbResult.length() - 1) == '零' && sbResult.length() != 1)
      sbResult.deleteCharAt(sbResult.length() - 1);
    if (strInteger.length() == 2) {
      replace(sbResult, "壹拾", "拾");
    }
    /** 将结果反转回来. */
    return sbResult.toString();
  }   /**
   * 转化小数部分例：输入22.34返回叁肆
   *
   * @param tempString
   * @return
   */
  private static String getFraction(String tempString) {
    String strFraction = null;
    int intDotPos = tempString.indexOf(".");
    /** 没有点说明没有小数，直接返回 */
    if (intDotPos == -1)
      return "";
    strFraction = tempString.substring(intDotPos + 1);
    StringBuffer sbResult = new StringBuffer(strFraction.length());
    for (int i = 0; i < strFraction.length(); i++) {
      sbResult.append(STR_NUMBER[strFraction.charAt(i) - 48]);
    }
    return sbResult.toString();
  }   /**
   * 判断传入的字符串中是否有.如果有则返回点
   *
   * @param tempString
   * @return
   */
  private static String getDot(String tempString) {
    return tempString.indexOf(".") != -1 ? "点" : "";
  }   /**
   * 判断传入的字符串中是否有-如果有则返回负
   *
   * @param tempString
   * @return
   */
  private static String getSign(String tempString) {
    return tempString.indexOf("-") != -1 ? "负" : "";
  }   /**
   * 将一个数字转化为金额
   *
   * @param tempNumber 传入一个double的变量
   * @return 返一个转换好的字符串
   */
  public static String numberToChinese(double tempNumber) {
    java.text.DecimalFormat df = new java.text.DecimalFormat("#.#########");
    String pTemp = String.valueOf(df.format(tempNumber));
    StringBuffer sbResult = new StringBuffer(getSign(pTemp) + getInteger(pTemp) + getDot(pTemp) + getFraction(pTemp));
    return sbResult.toString();
  }   public static String numberToChinese(BigDecimal tempNumber) {
    return numberToChinese(tempNumber.doubleValue());
  }   /**
   * 替代字符
   *
   * @param pValue
   * @param pSource
   * @param pDest
   */
  private static void replace(StringBuffer pValue, String pSource, String pDest) {
    if (pValue == null || pSource == null || pDest == null)
      return;
    /** 记录pSource在pValue中的位置 */
    int intPos = 0;
    do {
      intPos = pValue.toString().indexOf(pSource);
      /** 没有找到pSource */
      if (intPos == -1)
        break;
      pValue.delete(intPos, intPos + pSource.length());
      pValue.insert(intPos, pDest);
    } while (true);
  }   /**
   * @param args
   */
  public static void main(String[] args) {
    System.out.println(numberToChinese(1230400567.8934));
  }
}
自己想想怎么转回来吧....呵呵

又改了改,继续挑错
public class CSDN
{    public static String[] f = { "十", "百", "千", "万" };    public static int length = f.length - 1;    public String getNum(String str)
    {
        int num = change(str, length);
        if (num <0)
        {
            return "error";
        }
        return num + "";
    }    public int change(String str, int l)
    {
        int total = 0;
        if (l < 0)
        {
            total += wordToNum(str);
        }
        else
        {
            if(str.indexOf(f[l])<0)
            {
                total += change(str, l - 1);
            }
            else
            {
                String arr1[] = str.split(f[l]);                if (arr1.length > 2 && (l == 3))
                {
                    return -1;
                }
                else if (arr1.length >= 2)
                {
                    total += level(change(arr1[0], l), l);
                    total += change(arr1[1], l);
                }else
                {
                    total=level(wordToNum(arr1[0]),l);
                }
            }

        }
        return total;
    }    public int level(int str, int i)
    {
        int num = (int) ((Math.pow(10, i + 1)) * str);
        return num;
    }    public int wordToNum(String word)
    {
        int num = -999999999;
        String arr[] = { "零", "一", "二", "三", "四", "五", "六", "七", "八", "九", "十" };        for (int j = 0; j < length; j++)
        {
            if (word.endsWith(f[j]))
            {
                num = level(wordToNum(word.split(f[j])[0]), j);
                break;
            }
        }
        for (int i = 0, size = arr.length; i < size; i++)
        {
            if (word.equals(arr[i]) || word.equals("零" + arr[i]))
            {
                num = i;            }
        }
        return num;
    }    public static void main(String[] args)
    {
        String str = "六千零五十四万八千零九十";
        CSDN cal = new CSDN();        System.out.println(cal.getNum(str));
    }}

又又改了改,楼上的莫生气啊.
public class CSDN
{    public static String[] f = { "十", "百", "千", "万" };    public static int length = f.length - 1;    public String getNum(String str)
    {
        int num = change(str, length);
        if (num <0)
        {
            return "error";
        }
        return num + "";
    }    public int change(String str, int l)
    {
        int total = 0;
        if (l < 0)
        {
            total += wordToNum(str);
        }
        else
        {
            if(str.indexOf(f[l])<0)
            {
                total += change(str, l - 1);
            }
            else
            {
                String arr1[] = str.split(f[l]);                if (arr1.length > 2 && (l == 3))
                {
                    return -1;
                }
                else if (arr1.length >= 2)
                {
                    total += level(change(arr1[0], l), l);
                    total += change(arr1[1], l);
                }else
                {
                    total=level(change(arr1[0],l),l);
                }
            }

        }
        return total;
    }    public int level(int str, int i)
    {
        int num = (int) ((Math.pow(10, i + 1)) * str);
        return num;
    }    public int wordToNum(String word)
    {
        int num = -999999999;
        String arr[] = { "零", "一", "二", "三", "四", "五", "六", "七", "八", "九", "十" };        for (int j = 0; j < length; j++)
        {
            if (word.endsWith(f[j]))
            {
                num = level(wordToNum(word.split(f[j])[0]), j);
                break;
            }
        }
        for (int i = 0, size = arr.length; i < size; i++)
        {
            if (word.equals(arr[i]) || word.equals("零" + arr[i]))
            {
                num = i;            }
        }
        return num;
    }    public static void main(String[] args)
    {
        String str = "七零五万";
        CSDN cal = new CSDN();        System.out.println(cal.getNum(str));
    }}

盖楼public class CSDN
{    public static String[] f = { "十", "百", "千", "万" };    public static int length = f.length - 1;    public String getNum(String str)
    {
        int num = change(str, length);
        if (num < 0)
        {
            return "error";
        }
        return num + "";
    }    public int change(String str, int l)
    {
        int total = 0;
        if (l < 0)
        {
            total += wordToNum(str);
        }
        else
        {
            if(str.indexOf(f[l])<0)
            {
                total += change(str, l - 1);
            }
            else
            {
                String arr1[] = str.split(f[l]);                if (arr1.length > 2 && (l == 3))
                {
                    return -1;
                }
                else if (arr1.length >= 2)
                {
                    if(!"".equals(arr1[0]))
                    {
                        total += level(change(arr1[0], l), l);
                    }
                    else
                    {
                        total += level(change("一", l), l);
                    }

                    total += change(arr1[1], l);
                }else
                {
                    total=level(change(arr1[0],l),l);
                }
            }

        }
        return total;
    }    public int level(int str, int i)
    {
        int num = (int) ((Math.pow(10, i + 1)) * str);
        return num;
    }    public int wordToNum(String word)
    {
        int num = -999999999;
        String arr[] = { "零", "一", "二", "三", "四", "五", "六", "七", "八", "九", "十" };        for (int j = 0; j < length; j++)
        {
            if (word.endsWith(f[j]))
            {
                num = level(wordToNum(word.split(f[j])[0]), j);
                break;
            }
        }
        for (int i = 0, size = arr.length; i < size; i++)
        {
            if (word.equals(arr[i]) || word.equals("零" + arr[i]))
            {
                num = i;            }
        }
        return num;
    }    public static void main(String[] args)
    {
        String str = "一十五万零一十五";
        CSDN cal = new CSDN();        System.out.println(cal.getNum(str));
    }}

盖一下
public class CSDN
{    public static String[] f = { "十", "百", "千", "万" };    public static int length = f.length - 1;    public String getNum(String str)
    {
        int num = change(str, length);
        if (num < 0)
        {
            return "error";
        }
        return num + "";
    }    public int change(String str, int l)
    {
        int total = 0;
        if (l < 0)
        {
            total += wordToNum(str);
        }
        else
        {
            if(str.indexOf(f[l])<0)
            {
                total += change(str, l - 1);
            }
            else
            {
                String arr1[] = str.split(f[l]);                if (arr1.length > 2 && (l == 3))
                {
                    return -1;
                }
                else if (arr1.length >= 2)
                {
                    if("".equals(arr1[0])||"零".equals(arr1[0]))
                    {
                        total += level(change("一", l), l);
                    }
                    else
                    {
                        total += level(change(arr1[0], l), l);

                    }

                    total += change(arr1[1], l);
                }else
                {
                    total=level(change(arr1[0],l),l);
                }
            }

        }
        return total;
    }    public int level(int str, int i)
    {
        int num = (int) ((Math.pow(10, i + 1)) * str);
        return num;
    }    public int wordToNum(String word)
    {
        int num = -999999999;
        String arr[] = { "零", "一", "二", "三", "四", "五", "六", "七", "八", "九", "十" };        for (int j = 0; j < length; j++)
        {
            if (word.endsWith(f[j]))
            {
                num = level(wordToNum(word.split(f[j])[0]), j);
                break;
            }
        }
        for (int i = 0, size = arr.length; i < size; i++)
        {
            if (word.equals(arr[i]) || word.equals("零" + arr[i]))
            {
                num = i;            }
        }
        return num;
    }    public static void main(String[] args)
    {
        String str = "十五万零十五";
        CSDN cal = new CSDN();        System.out.println(cal.getNum(str));
    }}

重盖public class CSDN
{    public static String[] f = { "十", "百", "千", "万" };    public static int length = f.length - 1;    public String getNum(String str)
    {
        int num = change(str, length);
        if (num < 0)
        {
            return "error";
        }
        return num + "";
    }    public int change(String str, int l)
    {
        int total = 0;
        if (l < 0)
        {
            total += wordToNum(str);
        }
        else
        {
            if(str.indexOf(f[l])<0)
            {
                total += change(str, l - 1);
            }
            else
            {
                String arr1[] = str.split(f[l]);                if (arr1.length > 2 && (l == 3))
                {
                    return -999999999;
                }
                else if (arr1.length >= 2)
                {
                    if("".equals(arr1[0])||"零".equals(arr1[0]))
                    {
                        total += level(change("一", l), l);
                    }
                    else
                    {
                        total += level(change(arr1[0], l), l);

                    }

                    total += change(arr1[1], l);
                }else if(arr1.length==1)
                {
                    total=level(change(arr1[0],l),l);
                }
                else
                {
                    total += level(change("一", l), l);
                }
            }

        }
        return total;
    }    public int level(int str, int i)
    {
        int num = (int) ((Math.pow(10, i + 1)) * str);
        return num;
    }    public int wordToNum(String word)
    {
        int num = -999999999;
        String arr[] = { "零", "一", "二", "三", "四", "五", "六", "七", "八", "九", "十" };        for (int j = 0; j < length; j++)
        {
            if (word.endsWith(f[j]))
            {
                num = level(wordToNum(word.split(f[j])[0]), j);
                break;
            }
        }
        for (int i = 0, size = arr.length; i < size; i++)
        {
            if (word.equals(arr[i]) || word.equals("零" + arr[i]))
            {
                num = i;            }
        }
        return num;
    }    public static void main(String[] args)
    {
        String str = "万";
        CSDN cal = new CSDN();        System.out.println(cal.getNum(str));
    }}

我也看过了。现在应该可以了。把
if(r>max)
max *= r;
改为
if(r>max)
max = r;
应该也可以的。

我也写了一个，与上面各种方法思路不同。大家给验证验证。public class ChangeToNum {
    private static String numStr = "一二三四五六七八九";

    public ChangeToNum() {
     System.out.println(change("十一亿零五百万零十八"));
    }

    public static String change(String old){
     char[] newNum = new char[15];
     int temp = 1,max = 1,min = 1;
        old = old.replaceAll("零","");
        old = old.replaceAll("百十","百一十");
        old = old.replaceAll("千十","千一十");
        old = old.replaceAll("万十","万一十");
        old = old.replaceAll("亿十","亿一十");
        if(old.charAt(0)=='十')
            old = "一"+old;
        for(int i = 0;i<newNum.length;i++){
     newNum[i] = '0';
     }
     char ch;
     for(int i = old.length()-1;i>=0;i--){
     ch = old.charAt(i);
     if(numStr.indexOf(ch) != -1){
     temp = getNum(ch);
     newNum[newNum.length - min-max+1] = (char)(temp +48);
     }
     else{
     min = getNum(ch);
     if((min == 5 && max == 1)||(min == 9 && max < 9)){
     max = min;
     min = 1;
     }
     else if(max==9 && min==9){
     max += 9;
     min = 1;
     }
     }
     }
     return (new String(newNum)).substring(newNum.length - min-max+1);
    }

    private static int getNum(char ch){
     int index1 = numStr.indexOf(ch);
     int index2 = "十百千万零零零亿".indexOf(ch);
     if(index1 == -1 && index2 == -1){
     System.out.println("Fatal Error.");
     System.exit(0);
     }
     return index1 == -1?index2 + 2:index1 + 1;
    }

    public static void main(String[] args) {
        new ChangeToNum();
    }
}

有bug。把
            else{
                min = getNum(ch);
                if((min == 5 && max == 1)||(min == 9 && max < 9)){
                    max = min;
                    min = 1;
                }
                else if(max==9 && min==9){
                    max += 9;
                    min = 1;
                }
            }改为
     else{
     min = getNum(ch);
     if(min == 5)
     max += 4;
     else if(min == 9){
     if((max/4)%2 == 0)
     max +=8;
     else
     max +=4;
     }
     }应该可以了。

public class numberChange {

    /** Creates a new instance of numberChange */
    public numberChange() {
    }
    public int ChineseToNumber(String s)
    {
     s=s.replaceAll("零","");
        int len=s.length();
        int result=0;
        char c[]=new char[len];
        c=s.toCharArray();
        for(int i=0;i<len;i++)
        {
            if(len<=2)
            {
         switch(c[i])
         {
             case '一':c[i]='1';break;
             case '二':c[i]='2';break;
              case '三':c[i]='3';break;
               case '四':c[i]='4';break;
                case '五':c[i]='5';break;
                 case '六':c[i]='6';break;
                  case '七':c[i]='7';break;
                   case '八':c[i]='8';break;
                    case '九':c[i]='9';break;
                     case '十':c[i]='!';break;



         }

            }
            else
            {
             switch(c[i])
         {
             case '一':c[i]='1';break;
             case '二':c[i]='2';break;
              case '三':c[i]='3';break;
               case '四':c[i]='4';break;
                case '五':c[i]='5';break;
                 case '六':c[i]='6';break;
                  case '七':c[i]='7';break;
                   case '八':c[i]='8';break;
                    case '九':c[i]='9';break;
                     case '十':c[i]='!';break;
             case '百':c[i]='%';break;
             case '千':c[i]='&';break;
             case '万':c[i]='*';break;


         }




            }


        }
        for(int i=0;i<len;i++)
        {
         switch(c[i])
         {
             case '#':result=result+Integer.parseInt(String.valueOf(c[i-1]))*10;break;
             case '%':result=result+Integer.parseInt(String.valueOf(c[i-1]))*100;break;
             case '&':result=result+Integer.parseInt(String.valueOf(c[i-1]))*1000;break;
               case '*':result=result+Integer.parseInt(String.valueOf(c[i-1]))*10000;break;
             case '!':result=result+10;
         }



        }
     int   i=len-1;
       switch(c[i])
       {
       case '1':result=result+1;break;
             case '2':result=result+2;break;
              case '3':result=result+3;break;
           case '4':result=result+4;break;
                case '5':result=result+5;break;
                 case '6':result=result+6;break;
                  case '7':result=result+7;break;
                   case '8':result=result+8;break;
                    case '9':result=result+9;break;





       }
             return result;
    }








    }

调试易

求一个工具类，能把'一'，‘二’，‘二十一’等中文数字转换为阿拉伯数字1，2，21等

解决方案 »