public static void main(String[] args) {
try
{
DataInputStream di=new DataInputStream(System.in);
System.out.print(di.readInt());
}
catch(Exception ex)
{
System.out.print(ex.getMessage());
}
}总是得到奇怪的答案!
java的IO流真麻烦,有什么好书可以介绍的?
try
{
DataInputStream di=new DataInputStream(System.in);
System.out.print(di.readInt());
}
catch(Exception ex)
{
System.out.print(ex.getMessage());
}
}总是得到奇怪的答案!
java的IO流真麻烦,有什么好书可以介绍的?
try {
System.out.println("return:" + br.readLine());
}
catch (IOException ex) {
}
而DataInputStream应该去包装一个ByteArrayInputStream,
所以你这么弄肯定是错的了~~~~~