jquery 对比两个数组返回相同的数据

Question

jquery

Answer 1

var arr1=[1,2,3,4,5];
       var arr2=[2,4,6,8];
       var unix = new Array();
       for (var i = 0; i < arr1.length; i++) {
           if($.inArray(arr1[i] ,arr2) != -1){
            unix.push(arr1[i]);
           }
       }
       console.log(unix);

Answer 2

function intersection_destructive(a, b)
{
  var result = new Array();
  while( a.length > 0 && b.length > 0 )
  {  
     if      (a[0] < b[0] ){ a.shift(); }
     else if (a[0] > b[0] ){ b.shift(); }
     else /* they're equal */
     {
       result.push(a.shift());
       b.shift();
     }
  }  return result;
}
var arr1=[1,2,3,4,5]
var arr2=[2,4,6,8]alert(intersection_destructive(arr1,arr2));

Answer 3

坐等正侧方法，先上土方法：    var arr1=[1,2,3,4,5];
    var arr2=[2,4,6,8];
    var arr=arr1.concat(arr2);
        arr.sort();
    for(var i= 0,l=arr.length-1;i<l;i++){
        if(arr[i]===arr[i+1]){
            console.log(arr[i]);
            i++;
        }
    }

Answer 4

var arr1=[1,2,3,4,5];
var arr2=[2,4,6,8];
;(","+arr1+",|,"+arr2+",").replace(/,(\d+)(?=,.*\|.*,\1,)/ig,function(s,t){
alert(t);
});

Answer 5

var arr1=[1,2,3,4,5];
       var arr2=[2,4,6,8];
var  ar =arr1.filter(function(n) {
    return arr2.indexOf(n) != -1
});
alert(ar);

Answer 6

var arr1=[1,2,3,4,5]
  var arr2=[2,4,6,8]$.grep( arr1, function(n,i){
  return jQuery.inArray(n, arr)>-1;
});

Answer 7

var arr1=[1,2,3,4,5];
  var arr2=[2,4,6,8];$.grep( arr1, function(n,i){
  return jQuery.inArray(n, arr2)>-1;
});