怎样定义一个全局的拦截器？

Question

怎样定义一个全局的拦截器？

Answer 1

没做过，去看看struts2的资料吧

Answer 2

default-interceptor貌似有这个东西就是全局的。

Answer 3

这个很简单吧，网上拦截器的例子到处都是，public class SessionTimeoutInterceptor extends AbstractInterceptor{ @Override
public String intercept(ActionInvocation actionInvocation) throws Exception {
Map session = actionInvocation.getInvocationContext().getSession();
if (session.get("SPRING_SECURITY_CONTEXT")==null) {
outString("{timeout:true}");
return Action.NONE;
}else {
return actionInvocation.invoke();
}
}

public void outString(String str) {  
        HttpServletResponse response = ServletActionContext.getResponse();  
        try {  
            response.setHeader("Pragma", "No-cache");  
            response.setHeader("Cache-Control", "no-cache");  
            response.setDateHeader("Expires", 0);  
            response.setContentType("text/html;charset=gbk");  
            PrintWriter out = response.getWriter();  
            out.write(str);  
            out.flush();  
            out.close();  
        } catch (IOException e) {  
            e.printStackTrace();  
        }  
    }  
}

Answer 4

        <interceptors>
     <interceptor name="timeoutInterceptor" class="com.edward.SessionTimeoutInterceptor"></interceptor>
     <interceptor-stack name="timeoutStack">
     <interceptor-ref name="defaultStack"/>
     <interceptor-ref name="timeoutInterceptor"/>
     </interceptor-stack>
     </interceptors>
     <default-interceptor-ref name="timeoutStack"/>lz自己敲个例子，多测试下

Answer 5

<servlet-mapping> 
<servlet-name>actionServlet</servlet-name> 
<url-pattern>*.*</url-pattern> 
</servlet-mapping> 

Answer 6

<filter>
    <display-name>login</display-name>
    <filter-name>login</filter-name>
    <filter-class>login</filter-class>
  </filter>
  <filter-mapping>
    <filter-name>login</filter-name>
    <url-pattern>/*.jsp</url-pattern>
  </filter-mapping>中的
<url-pattern>/*.jsp</url-pattern>这样写就对了