因为网页编码的问题 导致数据库无法识别文字,高分回赠! 我的网页编码是UTF-8,Maestà是意大利语属于数据库里面的内容,第一页能把它读取出来,但是当我在网页上点击它然后在抛出这一条内容的时候(String c=request.getParameter("class");)在第二页就变成了MaestÃ,无法识别数据报错,想请问大牛们该怎么做才能让Maestà正确显示?我觉得应该就是编码的问题 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 在这行代码前加request.setCharacterEncoding("UTF-8")试试看 不行..显示下面错误HTTP Status 500 -type Exception reportmessagedescription The server encountered an internal error () that prevented it from fulfilling this request.exceptionorg.apache.jasper.JasperException: Exception in JSP: /link_ontology2.jsp:7067: <table border="1" align="center">68: <tr>69: 70: <td height="299" width="300" align="center"><%=q.ShowDetails2(c)%></td>71: <td height="599" width="440" align="center" rowspan="2"><%=q.ShowPhoto(c)%></td>72: 73: Stacktrace: org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:451) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:373) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:321) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:257) javax.servlet.http.HttpServlet.service(HttpServlet.java:729)root causejava.lang.NullPointerException com.query.Query1.ShowDetails2(Query1.java:542) org.apache.jsp.link_005fontology2_jsp._jspService(link_005fontology2_jsp.java:115) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:98) javax.servlet.http.HttpServlet.service(HttpServlet.java:729) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:331) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:321) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:257) javax.servlet.http.HttpServlet.service(HttpServlet.java:729) 先在servlet用这个方法解码!String boardName=request.getParameter("boardName");if(boardName!=null){ byte[] by=boardName.getBytes("ISO-8859-1"); String ss=new String(by,"UTF-8"); boardName=ss;} 不至于吧,设一个字符集后就Null了,原先就不Null?上面这一行代码是什么? 如果你是表单提交你把method="post"如果你是超链接提交request.setCharacterEncoding("UTF-8");String bordName = new String(request.getParameter("boardName").getBytes("ISO-8859-1"),"UTF-8"); 先在servlet用这个方法解码!String boardName=request.getParameter("boardName");if(boardName!=null){ byte[] by=boardName.getBytes("ISO-8859-1"); String ss=new String(by,"UTF-8"); boardName=ss;} 同意这种方法 但最好如楼上说的 先弄一个过滤器比较好 一般编码都采用UTF-8那样更好 请问这个代码如何设置? 求助一个struts2跳转问题 @Aspect 的异常,求助 很奇怪的关于页面转向问题(第一个可以成功转向第二个就不行)大家都来看一下!出出注意!!谢谢大家了! 求教个SQ查询L效率问题 logic:present name="accountBean" scope="session"这句话都代表什么意思呢 jar打包的问题,急急急 java servlet 存储过程 jsp Asp中有rs.addnew,jsp中有没有啊. 有关JBuilder5和Tomcat4结合的问题 继续做,还是辞职? Flex实时曲线图 如何 设定x轴的最大值?
不行..显示下面错误
HTTP Status 500 -type Exception reportmessagedescription The server encountered an internal error () that prevented it from fulfilling this request.exceptionorg.apache.jasper.JasperException: Exception in JSP: /link_ontology2.jsp:7067: <table border="1" align="center">
68: <tr>
69:
70: <td height="299" width="300" align="center"><%=q.ShowDetails2(c)%></td>
71: <td height="599" width="440" align="center" rowspan="2"><%=q.ShowPhoto(c)%></td>
72:
73:
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:451)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:373)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:321)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:257)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)root causejava.lang.NullPointerException
com.query.Query1.ShowDetails2(Query1.java:542)
org.apache.jsp.link_005fontology2_jsp._jspService(link_005fontology2_jsp.java:115)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:98)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:331)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:321)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:257)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
String boardName=request.getParameter("boardName");
if(boardName!=null){
byte[] by=boardName.getBytes("ISO-8859-1");
String ss=new String(by,"UTF-8");
boardName=ss;
}
上面这一行代码是什么?
request.setCharacterEncoding("UTF-8");
String bordName = new String(request.getParameter("boardName").getBytes("ISO-8859-1"),"UTF-8");
String boardName=request.getParameter("boardName");
if(boardName!=null){
byte[] by=boardName.getBytes("ISO-8859-1");
String ss=new String(by,"UTF-8");
boardName=ss;
} 同意这种方法 但最好如楼上说的 先弄一个过滤器比较好