---------------------------------------------------------------- -- Author :DBA_HuangZJ(發糞塗牆) -- Date :2014-07-07 13:40:35 -- Version: -- Microsoft SQL Server 2012 - 11.0.5058.0 (X64) -- May 14 2014 18:34:29 -- Copyright (c) Microsoft Corporation -- Enterprise Edition: Core-based Licensing (64-bit) on Windows NT 6.3 <X64> (Build 9600: ) (Hypervisor) -- ---------------------------------------------------------------- --> 测试数据:[PRS] if object_id('[PRS]') is not null drop table [PRS] go create table [PRS]([SerialNO] int,[uType] int,[sNO] int,[sDate] datetime) insert [PRS] select 107792,1,5,'20140609' union all select 107792,1,3,'20140609' union all select 107792,2,5,'20140610' union all select 100785,1,8,'20140610' --------------开始查询--------------------------SELECT SerialNO,SUM(sNO)sNO,MAX([sDate])[sDate] FROM ( select SerialNO , sNO ,[sDate] from [PRS] WHERE utype=1 UNION ALL select SerialNO , -1*sNO ,[sDate] from [PRS] WHERE utype=2)a GROUP BY SerialNO ORDER BY SerialNO DESC ----------------结果---------------------------- /* SerialNO sNO sDate ----------- ----------- ----------------------- 107792 3 2014-06-10 00:00:00.000 100785 8 2014-06-10 00:00:00.000 */
SELECT [SerialNO],SUM(CASE uTYPE WHEN 2 THEN -1*sNo ELSE sNo end )AS Quantity,MAX(sDate)sDate FROM A_J GROUP BY [SerialNO] ORDER BY SerialNo desc
-- Author :DBA_HuangZJ(發糞塗牆)
-- Date :2014-07-07 13:40:35
-- Version:
-- Microsoft SQL Server 2012 - 11.0.5058.0 (X64)
-- May 14 2014 18:34:29
-- Copyright (c) Microsoft Corporation
-- Enterprise Edition: Core-based Licensing (64-bit) on Windows NT 6.3 <X64> (Build 9600: ) (Hypervisor)
--
----------------------------------------------------------------
--> 测试数据:[PRS]
if object_id('[PRS]') is not null drop table [PRS]
go
create table [PRS]([SerialNO] int,[uType] int,[sNO] int,[sDate] datetime)
insert [PRS]
select 107792,1,5,'20140609' union all
select 107792,1,3,'20140609' union all
select 107792,2,5,'20140610' union all
select 100785,1,8,'20140610'
--------------开始查询--------------------------SELECT SerialNO,SUM(sNO)sNO,MAX([sDate])[sDate]
FROM (
select SerialNO , sNO ,[sDate] from [PRS]
WHERE utype=1
UNION ALL
select SerialNO , -1*sNO ,[sDate] from [PRS]
WHERE utype=2)a
GROUP BY SerialNO
ORDER BY SerialNO DESC
----------------结果----------------------------
/*
SerialNO sNO sDate
----------- ----------- -----------------------
107792 3 2014-06-10 00:00:00.000
100785 8 2014-06-10 00:00:00.000
*/
FROM A_J
GROUP BY [SerialNO]
ORDER BY SerialNo desc