select ( select count(*) from A where col1 in (select col from B))+(select count(*) from A where col2 in (select col from B))+(select count(*) from A where col3 in (select col from B))
补充说明create table test1 ( id1 varchar(10), name1 varchar(20) ) insert into test1 values('01','a1,a2,a3'); insert into test1 values('02','a1,a6,a3');create table test2 ( id2 varchar(10), name2 varchar(20) ) insert into test2 values('1','a1'); insert into test2 values('2','a2'); insert into test2 values('3','a3'); insert into test2 values('4','a4'); insert into test2 values('5','a5'); 统计结果为 5 即test1的name1的某一部分出现在test2 name2中即加1
select count(*) from test1 where exists (select 1 from test2 where find_in_set(test2.name2,test1name1))
SELECT COUNT(A.ID1) FROM test1 A LEFT JOIN TEST2 B ON INSTR(A.`name1`,B.`name2`)>0
建议你列出你的表结构,并提供测试数据以及基于这些测试数据的所对应正确结果。
参考一下这个贴子的提问方式http://topic.csdn.net/u/20091130/20/8343ee6a-417c-4c2d-9415-fa46604a00cf.html
1. 你的 create table xxx .. 语句
2. 你的 insert into xxx ... 语句
3. 结果是什么样,(并给以简单的算法描述)
4. 你用的数据库名称和版本(经常有人在MS SQL server版问 MySQL)
这样想帮你的人可以直接搭建和你相同的环境,并在给出方案前进行测试,避免文字描述理解上的误差。
select count(*)
from A
where col1 in (select col from B))+(select count(*)
from A
where col2 in (select col from B))+(select count(*)
from A
where col3 in (select col from B))
(
id1 varchar(10),
name1 varchar(20)
)
insert into test1 values('01','a1,a2,a3');
insert into test1 values('02','a1,a6,a3');create table test2
(
id2 varchar(10),
name2 varchar(20)
)
insert into test2 values('1','a1');
insert into test2 values('2','a2');
insert into test2 values('3','a3');
insert into test2 values('4','a4');
insert into test2 values('5','a5');
统计结果为 5 即test1的name1的某一部分出现在test2 name2中即加1
from test1
where exists (select 1 from test2 where find_in_set(test2.name2,test1name1))