一条简单Sql排序语句 select name,result,count(*) over(partition by name) num from table order by num,name 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 select b.*(select name,count(*) times from table1 where result ='奖'group by nameorder by times) a ,table1 bwhere a.name = b.nameorder by a.times select name,count(result) num from table group by name order by num select name,result,icount from(select name,result,count(result) as icount from test group by name,result) order by icount desc 上面语句可以简写成:select name,result,count(result) as icount from test group by name,result order by icount desc pl\sql 行列转换问题 求月份的问题~~ 求一关于日期的sql语句,急!11 oracle 時間小問題~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 问一个看似很简单的问题:关于唯一的 [100分]在pl/sql中是否有indexOf索引函数和substring截取函数吗的吗?如果有如何使用[急等] java存储过程----不能加载类 谁来帮帮我啊? 请教大家,怎么能用导出的sql文件在access中导入数据呢 怎样drop一张表上的所有index???? 请教高手! 一个较难的SQL问题,如何写?大家帮忙了
(select name,count(*) times from table1 where result ='奖'
group by name
order by times) a ,table1 b
where a.name = b.name
order by a.times
from(select name,result,count(result) as icount from test group by name,result)
order by icount desc
select name,result,count(result) as icount from test group by name,result
order by icount desc