特定行之间求和

TO: baojianjun(包子) 这样还是不行的！！

ROWNUM 不能这样用select SUM(FEE_ALL) FEE_ALL FROM (select FEE_ALL,rownum r from table where rownum<10) where r>0;

看各例子：
SQL> SELECT * FROM BAO_TEMP
  2  WHERE ROWNUM BETWEEN 1 AND 4
  3  /PART_ID                        USER_1
------------------------------ ---------
1031015A
1031015B
1031015C
1154018ASQL> SELECT * FROM BAO_TEMP
  2  WHERE ROWNUM BETWEEN 2 AND 4
  3  /沒有任何資料列被選取由上面例子可以知道，你的
UNION ALL
SELECT SUM(FEE_ALL) FROM TABLE WHERE ROWNUM BETWEEN 11 AND 21
UNION ALL
SELECT SUM(FEE_ALL) FROM TABLE WHERE ROWNUM BETWEEN 21 AND 31
語句是取步道數據的
關於如何使用ROWNUM返回對應記錄數我給你貼一篇文章：[转贴]如何正确利用Rownum来限制查询所返回的行数？
软件环境：
1、Windows NT4.0+ORACLE 8.0.4
2、ORACLE安装路径为：C:\ORANT 含义解释：
1、rownum是oracle系统顺序分配为从查询返回的行的编号，返回的第一行分配的是1，第二行是2，
　依此类推，这个伪字段可以用于限制查询返回的总行数。
2、rownum不能以任何基表的名称作为前缀。
使用方法：
现有一个商品销售表sale，表结构为：
month　　　 char(6)　　　　　 --月份
sell　　　　number(10,2)　　　--月销售金额 create table sale (month char(6),sell number);
insert into sale values('200001',1000);
insert into sale values('200002',1100);
insert into sale values('200003',1200);
insert into sale values('200004',1300);
insert into sale values('200005',1400);
insert into sale values('200006',1500);
insert into sale values('200007',1600);
insert into sale values('200101',1100);
insert into sale values('200202',1200);
insert into sale values('200301',1300);
insert into sale values('200008',1000);
commit; SQL> select rownum,month,sell from sale where rownum=1;（可以用在限制返回记录条数的地方，保证不出错，如：隐式游标）    ROWNUM MONTH       SELL
--------- ------ ---------
        1 200001      1000 SQL> select rownum,month,sell from sale where rownum=2;（1以上都查不到记录）没有查到记录 SQL> select rownum,month,sell from sale where rownum>5;
（由于rownum是一个总是从1开始的伪列，Oracle 认为这种条件不成立，查不到记录）
没有查到记录只返回前3条纪录
SQL> select rownum,month,sell from sale where rownum<4;    ROWNUM MONTH       SELL
--------- ------ ---------
        1 200001      1000
        2 200002      1100
        3 200003      1200
如何用rownum实现大于、小于逻辑？（返回rownum在4—10之间的数据）（minus操作，速度会受影响）
SQL> select rownum,month,sell from sale where rownum<10
  2  minus
  3  select rownum,month,sell from sale where rownum<5;    ROWNUM MONTH       SELL
--------- ------ ---------
        5 200005      1400
        6 200006      1500
        7 200007      1600
        8 200101      1100
        9 200202      1200 想按日期排序，并且用rownum标出正确序号（有小到大）
SQL> select rownum,month,sell from sale order by month;    ROWNUM MONTH       SELL
--------- ------ ---------
        1 200001      1000
        2 200002      1100
        3 200003      1200
        4 200004      1300
        5 200005      1400
        6 200006      1500
        7 200007      1600
       11 200008      1000
        8 200101      1100
        9 200202      1200
       10 200301      1300 查询到11记录. 可以发现，rownum并没有实现我们的意图，系统是按照记录入库时的顺序给记录排的号，rowid也是顺序分配的 SQL> select rowid,rownum,month,sell from sale order by rowid; ROWID                 ROWNUM MONTH       SELL
------------------ --------- ------ ---------
000000E4.0000.0002         1 200001      1000
000000E4.0001.0002         2 200002      1100
000000E4.0002.0002         3 200003      1200
000000E4.0003.0002         4 200004      1300
000000E4.0004.0002         5 200005      1400
000000E4.0005.0002         6 200006      1500
000000E4.0006.0002         7 200007      1600
000000E4.0007.0002         8 200101      1100
000000E4.0008.0002         9 200202      1200
000000E4.0009.0002        10 200301      1300
000000E4.000A.0002        11 200008      1000 查询到11记录. 正确用法，使用子查询
SQL> select rownum,month,sell from (select month,sell from sale group by month,sell) where rownum<13;    ROWNUM MONTH       SELL
--------- ------ ---------
        1 200001      1000
        2 200002      1100
        3 200003      1200
        4 200004      1300
        5 200005      1400
        6 200006      1500
        7 200007      1600
        8 200008      1000
        9 200101      1100
       10 200202      1200
       11 200301      1300 按销售金额排序，并且用rownum标出正确序号（有小到大）
SQL> select rownum,month,sell from (select sell,month from sale group by sell,month) where rownum<13;    ROWNUM MONTH       SELL
--------- ------ ---------
        1 200001      1000
        2 200008      1000
        3 200002      1100
        4 200101      1100
        5 200003      1200
        6 200202      1200
        7 200004      1300
        8 200301      1300
        9 200005      1400
       10 200006      1500
       11 200007      1600 查询到11记录. 利用以上方法，如在打印报表时，想在查出的数据中自动加上行号，就可以利用rownum。返回第5—9条纪录，按月份排序
SQL> select * from (select rownum row_id ,month,sell
  2  from (select month,sell from sale group by month,sell))
  3  where row_id between 5 and 9;     ROW_ID MONTH        SELL
---------- ------ ----------
         5 200005       1400
         6 200006       1500
         7 200007       1600
         8 200008       1000
         9 200101       1100

試試這樣些寫：
CREATE TABLE TEST
AS
SELECT SUM(FEE_ALL) FEE_ALL FROM TABLE WHERE ROWNUM BETWEEN 0 AND 11
UNION
SELECT SUM(FEE_ALL) FROM (
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 22
       MIMUS
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 12  )
UNION
SELECT SUM(FEE_ALL) FROM (
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 32
       MIMUS
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 22  )

TO :baojianjun(包子)  CREATE TABLE TEST
AS
SELECT SUM(FEE_ALL) FEE_ALL FROM TABLE WHERE ROWNUM BETWEEN 0 AND 11
UNION
SELECT SUM(FEE_ALL) FROM (
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 22
       MIMUS
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 12  )
报错：missing left parenthesis
－－－－－－－－－－－－－－－－－－－－－－－－－－－－－－－－－
SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 22
       MIMUS
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 12
还是报错：missing left parenthesis

不好意思寫錯了：）
CREATE TABLE TEST
AS
SELECT SUM(FEE_ALL) FEE_ALL FROM TABLE WHERE ROWNUM BETWEEN 0 AND 11
UNION
SELECT SUM(FEE_ALL) FROM (
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 22
       MINUS  --應該是'MINUS'而不是'MIMUS'
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 12  )
UNION
SELECT SUM(FEE_ALL) FROM (
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 32
       MINUS
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 22  )附加例子：
  1  SELECT PART_ID FROM BAO_TEMP
  2  WHERE ROWNUM<6
  3  UNION
  4  SELECT PART_ID FROM
  5  (SELECT PART_ID FROM BAO_TEMP
  6  WHERE ROWNUM<11
  7  MINUS
  8  SELECT PART_ID FROM BAO_TEMP
  9* WHERE ROWNUM<6)
SQL> /PART_ID
------------------------------
1031015A
1031015B
1031015C
1154018A
1154022A
2072010A
2072120A
2072121A
2096011A
2096015A選取了 10 列

假如我对所得的和安顺序排列
CREATE TABLE TEST
AS
SELECT SUM(FEE_ALL) FEE_ALL FROM TABLE WHERE ROWNUM BETWEEN 0 AND 11
UNION
SELECT SUM(FEE_ALL) FROM (
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 22
       MINUS  --應該是'MINUS'而不是'MIMUS'
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 12  )
UNION
SELECT SUM(FEE_ALL) FROM (
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 32
       MINUS
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 22  )
ORDER BY FEE_ALL DESC为什么会报错：非法的列名！

改成這樣就可以了：
CREATE TABLE TEST
AS
SELECT SUM(FEE_ALL) FEE_ALL FROM TABLE WHERE ROWNUM BETWEEN 0 AND 11
UNION
SELECT SUM(FEE_ALL) FEE_ALL FROM (
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 22
       MINUS  --應該是'MINUS'而不是'MIMUS'
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 12  )
UNION
SELECT SUM(FEE_ALL) FEE_ALL FROM (
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 32
       MINUS
       SELECT FEE_ALL FROM TABLE WHERE  ROWNUM < 22  )
ORDER BY FEE_ALL DESC舉例：  1  SELECT SUM(CYC_TIME) CYC_TIME FROM PCSHD_PARAM_CONF
  2  WHERE ROWNUM<6
  3  UNION
  4  SELECT SUM(CYC_TIME) CYC_TIME FROM
  5        (SELECT CYC_TIME  FROM PCSHD_PARAM_CONF
  6         WHERE ROWNUM<11
  7         MINUS
  8         SELECT CYC_TIME  FROM PCSHD_PARAM_CONF
  9          WHERE ROWNUM<6
10        )
11* ORDER BY CYC_TIME
SQL> /  CYC_TIME
----------
       1.5
       5.6

ORDER BY item must be the number of a SELECT-list expression所以必須用偽列來代替原來的列名，才能進行ORDER BY

调试易

特定行之间求和

解决方案 »