急~~~~~~PHP如何获取新添加记录的ID值

Question

<?php
session_start();
require_once '../inc/const.php';
$_POST = eval('return ' . iconv('gb2312', 'utf-8', var_export($_POST, true)) . ';');$id         =getvar('id');
$name  =getvar('name');
$addr  =getvar('addr');
$httpurl =getvar('httpurl');
$tel =getvar('tel');
$mobile =getvar('mobile');
$fax  =getvar('fax');
$email  =getvar('email');
$qq  =getvar('qq');
$area  =getvar('area');
$industry =getvar('industry'); 
$rank =getvar("rank");$temp_fwnr = "";
$fwnr = $_POST['fwnr'];
for($i=0;$i<count($fwnr);$i++){
$service_start = "service_start".$fwnr[$i];
$service_end = "service_end".$fwnr[$i];
$service_content = "service_content".$fwnr[$i];
$temp_services = $fwnr[$i].",".$_POST[$service_start].",".$_POST[$service_end].",".$_POST[$service_content];
$temp_fwnr = empty($temp_fwnr) ? $temp_services : $temp_fwnr."|".$temp_services;

}if($act=='add'){
$record = array(
'name' =>$name,
'addr' =>$addr,
'httpurl' =>$httpurl,
'tel' =>$tel,
'mobile' =>$mobile,
'fax' =>$fax,
'email' =>$email,
'qq' =>$qq,
'area' =>$area,
'industry' =>$industry,
    'services' =>$temp_fwnr,
'rank' =>$rank,
'dateline' =>date("y-m-d H-i-s")
);
$id = $db->insert($GLOBALS[databasePrefix].'customer',$record);
//if (isset($_POST['id'])) {
     //echo "你的编号是:". $_POST['id'];
//}
if (var_dump($_POST['$id'])){
     echo "你的编号是:". $_POST['$id'];
}if (isset($_POST['name'])) {
     echo "你的名字是:". $_POST['name'];
}
}
?>
编号也就是ID号，  当前提交表单的id号输不出来。要怎么才可以输出来啊？？？？？？？

Answer 1

mysql_insert_id(); 获得上条插入数据的ID

Answer 2

$id=mysql_insert_id();这样就获得上条刚刚插入记录的ID值了，很简单的

Answer 3

<?php
session_start();
require_once '../inc/const.php';
$_POST = eval('return ' . iconv('gb2312', 'utf-8', var_export($_POST, true)) . ';');$id         =getvar('id');
$name         =getvar('name');
$addr         =getvar('addr');
$httpurl    =getvar('httpurl');
$tel        =getvar('tel');
$mobile        =getvar('mobile');
$fax         =getvar('fax');
$email         =getvar('email');
$qq         =getvar('qq');
$area         =getvar('area');
$industry    =getvar('industry'); 
$rank        =getvar("rank");$temp_fwnr = "";
$fwnr = $_POST['fwnr'];
for($i=0;$i<count($fwnr);$i++){
    $service_start = "service_start".$fwnr[$i];
    $service_end = "service_end".$fwnr[$i];
    $service_content = "service_content".$fwnr[$i];
    $temp_services = $fwnr[$i].",".$_POST[$service_start].",".$_POST[$service_end].",".$_POST[$service_content];
    $temp_fwnr = empty($temp_fwnr) ? $temp_services : $temp_fwnr."|".$temp_services;
    
}if($act=='add'){
    $record = array(
        'name'        =>$name,
        'addr'        =>$addr,
        'httpurl'    =>$httpurl,
        'tel'        =>$tel,
        'mobile'    =>$mobile,
        'fax'        =>$fax,
        'email'        =>$email,
        'qq'        =>$qq,
        'area'        =>$area,
        'industry'    =>$industry,
        'services'    =>$temp_fwnr,
        'rank'        =>$rank,
        'dateline'    =>date("y-m-d H-i-s")
    );
    $db->insert($GLOBALS[databasePrefix].'customer',$record);
    $id = mysql_insert_id();
//if (isset($_POST['id'])) {
     //echo "你的编号是:". $_POST['id'];
//}
if (var_dump($_POST['$id'])){
     echo "你的编号是:". $_POST['$id'];
}if (isset($_POST['name'])) {
     echo "你的名字是:". $_POST['name'];
}
}
?>

Answer 4

按照楼上的方法  输出的是：NULL

Answer 5

把四楼的红字部分改为 $id=$db->lastInsertId();//最后一次插入记录的id号