数据库中表为个人信息表,有性别字段,用ThinkPHP从数据库中取出数据之后,如何根据结果,改变表单中<input type = "radio" name = "sex" value = "男" />男 <input type = "radio" name = "sex" value = "女" />女那个单选框被选中呢?
小弟再ThinkPHP手册上看到了if标签,就采用了一下,解决方法如下可以:<if condition = "$vo.sex eq '男'"> <input type = "radio" name = "sex" value = "男" checked />男 <input type = "radio" name = "sex" value = "女" />女 <else /> <input type = "radio" name = "sex" value = "男" />男 <input type = "radio" name = "sex" value = "女" checked />女 </if>但是小弟还是求教二楼的大虾给的方法怎么处理?
<input type = "radio" name = "sex" value = "男" <?php echo $sex=='男' ? 'checked' : '';?> />男
<input type = "radio" name = "sex" value = "女" <?php echo $sex=='女' ? 'checked' : '';?> />女
<input type = "radio" name = "sex" value = "男" checked />男
<input type = "radio" name = "sex" value = "女" />女
<else />
<input type = "radio" name = "sex" value = "男" />男
<input type = "radio" name = "sex" value = "女" checked />女
</if>但是小弟还是求教二楼的大虾给的方法怎么处理?
男
<else/>
女
</if>