$a = Array
(
[0] => 3
[1] => 1
[2] => 2
[3] => 7
)$b = Array
(
[1] => Emross War
[2] => Roman Empire
[3] => Avalon Wars
[7] => 掌上三国
[9] => 罗马(91)
[10] => Space Dominions
[11] => 腾讯三国
[12] => Vampire War
[15] => 三国英雄传
[17] => 掌上水浒
)
$a数组中的值是$b 的键值那我如何得到
$c = Array
(
[1] => Emross War
[2] => Roman Empire
[3] => Avalon Wars
[7] => 掌上三国
)求大侠给个答案
php数组
(
[0] => 3
[1] => 1
[2] => 2
[3] => 7
)$b = Array
(
[1] => Emross War
[2] => Roman Empire
[3] => Avalon Wars
[7] => 掌上三国
[9] => 罗马(91)
[10] => Space Dominions
[11] => 腾讯三国
[12] => Vampire War
[15] => 三国英雄传
[17] => 掌上水浒
)
$a数组中的值是$b 的键值那我如何得到
$c = Array
(
[1] => Emross War
[2] => Roman Empire
[3] => Avalon Wars
[7] => 掌上三国
)求大侠给个答案
php数组
(
0 => 3,
1 => 1,
2 => 2,
3 => 7
);$b = Array
(
1 => 'Emross War',
2 => 'Roman Empire',
3 => 'Avalon Wars',
7 => '掌上三国',
9 => '罗马(91)',
10 =>'Space Dominions',
11 =>'腾讯三国',
12 =>'Vampire War',
15 =>'三国英雄传',
17 =>'掌上水浒'
);
foreach($a as $k){
$c[$k]=$b[$k];
}
ksort($c);
print_r($c);
$c = array(); //定义一个结果数组
foreach($a as $k) { // 依次从数组 $b 中取值
$c[$k] = $b[$k];
}
(
'0' => 3,
'1' => 1,
'2' => 2,
'3' => 7
);$b = Array
(
'1' => 'Emross War',
'2' => 'Roman Empire',
'3' => 'Avalon Wars',
'7' => '掌上三国',
'9' => '罗马(91)',
'10' => 'Space Dominions',
'11' => '腾讯三国',
'12' => 'Vampire War',
'15' => '三国英雄传',
'17' => '掌上水浒',
);
$c = array_flip($a); //array_flip -- 交换数组中的键和值
$d = array_intersect_key($b, $c); //array_intersect_key -- 使用键名比较计算数组的交集
print_r($d);
$a = array
(
3,1,2,7
);$b = array
(
'1' => 'Emross War',
'2' => 'Roman Empire',
'3' => 'Avalon Wars',
'7' => '掌上三国',
'9' => '罗马(91)'
);
$c = array();
foreach($a as $key=>$val){
if(in_array($a[$key],array_keys($b))){
$c[$val]=$b[$a[$key]];
}
}
print_r($c);